6|-5| - 3(2/3) + 7(-8)=

-88
-16
-28

Answers

Answer 1

Answer:

-28

Step-by-step explanation:

6|-5| - 3(2/3) + 7(-8)=

30 -2 -56

30 -58 = -28


Related Questions

Xavier opened a savings account with a deposit of $12,000. the account earned simple interest. he did not make any additional deposits or withdrawals. at the end of 3 years, the account balance was $12,324. what is the annual interest rate on this account? question 5 options: 0.9% 1.8% 2.7% 3.6%

Answers

Answer:

0.9%

Step-by-step explanation:

I took the test

The graph of p = 400 and the graph of p = 50s – 200 intersect at the point (12,400). If the equation p = 50s – 200 represents the profit, p, based on s sales, what does the intersection best represent?

a. When the sales are 400, the profit is 12.
b. When the sales are 12, the profit is 400.
c. The profit is always 400.
d. The sales are always 12.

Answers

When sales 12 profit is 400 which is B

-3y (y⁴ + 2y³ - 5y²- y + 4)​

Answers

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's expand the given expression ~

[tex]\qquad \sf  \dashrightarrow \: - 3y( {y}^{4} + 2 {y}^{3} - 5 {y}^{2} - y + 4)[/tex]

[tex]\qquad \sf  \dashrightarrow \: ( - 3y \cdot {y}^{4} ) + ( - 3y \cdot2 {y}^{3} ) + ( - 3y \cdot - 5 {y}^{2} ) + ( - 3y \cdot - y) + ( - 3y \cdot4)[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 3{y}^{5} - 6{y}^{4} + 1 5 {y}^{3} + 3{y}^{2} - 12y[/tex]

Please help fast i I’ll give brainliest

Answers

Answer:

The answer is B. 1/4^8

Step-by-step explanation:

Every time the power it to the negative it inverse it.

An example, 2^-2 = 1 / 2^2

So, 4^-8 = 1 / 4^8

Distribute to create an equivalent expression with the fewest symbols possible.
6(3c - 5d + 6) =6(3c−5d+6)=6, left parenthesis, 3, c, minus, 5, d, plus, 6, right parenthesis, equals

Answers

Using the distributive property, it is found that the equivalent expression is:

18c - 30d + 36

What is the distributive property?

It is a property that the outside term multiplies each of the inside terms.

In this problem, the expression is:

6(3c - 5d + 6).

Hence, we apply the property, with the outside term 6 multiplying each of the inside terms, hence the equivalent expression is given by:

6(3c - 5d + 6) = 18c - 30d + 36.

More can be learned about the distributive property at https://brainly.com/question/2807928

Question 7 of 10
One spring, a group of students measured rainfall totals at their school. This
chart shows how many inches of rain the students measured each month.
How many more inches did it rain in May than in April?
RAINFALL
MONTH
March
April
May
5.7
3.2
7.3
Help me god

Answers

Answer:

9

Step-by-step explanation:

10

A box of chocolates contains five milk chocolates, five dark chocolates, and three white chocolates. You randomly select and eat three chocolates. The first piece is milk chocolate, the second is white chocolate, and the third is milk chocolate.

Answers

Answer:

2/7

Step-by-step explanation:

Total no. of chocolates in the box =14

No. of dark Chocolates=4

No. of white chocolates=5

No. of milk chocolates=5

Probability of getting a white chocolate

= No. of possible outcomes /Total No. of outcomes

=5/14

Probability of getting a dark chocolate =4/14=2/7

Calculate the perimeter of of the shape below. Show you work

Answers

Answer:

22 is the perimeter.

Step-by-step explanation:

You find the perimeter by adding up all of the sides of a shape. 9 + 9 = 18. 18 + 4 = 22.

Which number is equivalent to 5×10+4×1+8×110+6×1100+1×11,000?

Answers

Answer:

54861/1000 convert to a decimal = 54.861

B. Study the figure on the right.
1. Name the points on it
2 Name any three segments from the figure,
3. Which segments have B as one endpoint?
4. Which points are endpoints of only two segments?
5. Which points are endpoints of three segments?
6. Which point is the endpoint of six segments?
7. Name the lines with A as one of the points on them.
8. Name any three rays from the figure, 9. How many segments are there in the figure?
10. How many rays can be named from the figure?​

Answers

Answer:

can you clear more I don't understand

ALL of the Students at Beach Middle School voted for a trip to the zoo or the aquarium.
- 25% of the students voted for the aquarium
- 120 students voted for the zoo
What is the total number of students at Beach Middle School?

Answers

Answer:

160

Step-by-step explanation:

If there were only 2 options, all the people who didn't pick one chose the other one.

So if 25% of the people voted for the aquarium the remaing 75% voted for the zoo.

Since three times as many people voted for the zoo, we can see that 120/3=40, so 40 people chose the aquarium.

To find the total number of students, we add 120 and 40 to get 160

What is the answer to this?

Answers

Answer:

0.216 cubic feet

Step-by-step explanation:

v = lwh (volume = length times width times height)

v = 0.6 x 0.6 x 0.6  OR 0.6^3

v = 0.216

Use the picture I provided to help me answer the math problem.

Answers

Part A

25%/100%1/4

Part B

1 → 20 pieces 4 → (20*4) pieces 4 → 80 pieces of yellow paper

Answer:

See below ↓↓

Step-by-step explanation:

Part A

We have to write 25% as a rate per 100⇒ We know percentages are given to be the fraction of a number out of 100⇒ Therefore, 25% as rate per 100 = 25/1001/4 [simplified]

Part B

Let's take the total number of pieces of colored paper to be TThen 25% of T is 20Therefore our equation will be :⇒ T x 25/100 = 20Bring 100 to the other side⇒ 25T = 200025 is a factor of both 25 and 2000, so it cancels out, and we are left with :⇒ T = 80There are 80 pieces of paper

does anybody know the answer to this question?

Answers

Answer: 56 yd

Step-by-step explanation: if you continue the 8 yd line across, it would show that the missing side is 4yd less than the 13 yd side, meaning the missing side is 9 yd long. So after adding 7 + 13+ 15+ 4 + 8 + 9= 56 yd

A bullet fired up in the air attains a height of g(x) = 14x2 + 48x - 4 feet after x seconds. Find the
average rate of change of g between X = 1 and X = 3

Answers

Answer:

104ft/s

Step-by-step explanation:

[tex]\frac{f(b)-f(a)}{b-a}=\frac{f(3)-f(1)}{3-1}=\frac{266-58}{2}=\frac{208}{2}=104[/tex]

Thus, the average rate of change of the function between x=1 and x=3 is 104ft/s

Help me











Question
Find mHK⌢.

Answers

Answer:

62

Step-by-step explanation:

(x+8)=(2x-15)
8=x-15
+15   +15
23=x

so


23 +8 = 31
23x2-15 = 46-15 =31
Both are the same always since one side is equal to the other
Therefore
62 is the answer!

The graph of the function f(x)=x^2-6x shifted 2 units to the left on the graph of g(x). Select the two functions that represent the shift of f(x) onto g(x)

Answers

The correct answer is

g(x) =f(x+2)
And

g(x)=x^2-2x-8

omg please help its due by 12 am! the sum of 2 numbers is 69. the larger number is 3 less than twice the smaller number .find the numbers. show your work!

Answers

Answer:

The smaller number is 24

The larger number is 45

Step-by-step explanation:

smaller number  = x

Larger: 2x - 3

Smaller + larger = 69

x + 2x - 3 = 69                        Combine left

3x - 3 = 69                              add 3 to both sides

3x - 3+3 = 69+ 3                     Combine

3x = 72                                    Divide by 3

3x/3 = 72/3                        

x = 24

Larger number = 2*24 - 3

Larger number = 45

A study of a population of 1,200 tigers revealed that 6 out of every 150 tigers in the
population are albino. Based on the results of this study, how many tigers in the population
are NOT albino?

Answers

Answer:  1152

========================================================

Explanation:

6/150 = 0.04 = 4% of the population are albino.

That leaves 100% - 4% = 96% that aren't albino.

96% of 1200 = 0.96*1200 = 1152

------------

Another way to look at it:

4% of the population are albino, so there are 0.04*1200 = 48 albino tigers.

This means there are 1200-48 = 1152 non-albino tigers.

Sandro plans to travel to work by train on 20 days next month. He can buy a monthly ticket costing £262 or 20 separate tickets costing £15.70 each ticket. What percentage of the total cost of 20 separate tickets does Sandro save by buying a monthly ticket? Give your answer correct to 1 decimal place.

Answers

20 separate tickets in total costs £314.

Now we should find out what percentage 262 is of 314.

262÷314×100=83.4%

if 262 is 83.4% of 314, then Sandro saves (100%-83.4%) 16.6%.

ANSWER 16.6%

qartveli xar mgoni dd

Solve for x.
С
D
*
112°

(2x)
>>
A
B

Answers

the answer would be 112, best of luck!

4. Find the arc length.

Answers

Find the circumference:

8km x 2 x 3.14 = 50.24 km

Arc length = 50.24 x 225/360 = 31.4 km


answer: C. 10 pi or 31.4 km


Given conversion factor what is the above line segment's unit
1 ft
measure in inches? Round your answer to the nearest tenth.
Answer here
Please help

Answers

Answer:

24

Step-by-step explanation:

[tex]Convert\ the\ unit\ for\ \frac{12in}{1ft}:\\ \downarrow\\ 24[/tex]

I hope this helps you

:)

Hello ! Here's a calculus question!

Find that value of

[tex]\\ \rm\Rrightarrow {\displaystyle{\int\limits_{\pi}^{2\pi}}}\dfrac{sin^6x+cos^6x}{sin^3xcos^3x}[/tex]


Note:-

Answer must include all steps properly .

Kindly don't waste time here if you don't know the answer .

All the best !​

Answers

Answer:

Undefined.

Formula's used:

[tex]\longrightarrow \bold{sec(x) = \dfrac{1}{cos(x)} }[/tex]

[tex]\longrightarrow \bold{cosec(x) = \dfrac{1}{sin(x)} }[/tex]

[tex]\longrightarrow \bold{cot(x) = \dfrac{1}{tan(x)} }[/tex]

[tex]\longrightarrow \bold{tan(x) = \dfrac{sinx}{cos(x)} }[/tex]

[tex]\longrightarrow \bold{sin^2x + cos^2 x = 1 }[/tex]

[tex]\longrightarrow \sf \bold{Sum \ Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx}[/tex]

[tex]\longrightarrow \bold{ \int \:{sec^2(ax+b) = \dfrac{1}{a}tan(ax+b)+c }}[/tex]

[tex]\longrightarrow \bold{\int \:\dfrac{1}{ax+b} =\dfrac{1}{a} ln|ax+b|+c}[/tex]

Explanation:

[tex]\sf \Longrightarrow \int _{\pi }^{2\pi }\:\dfrac{sin^6(x)+cos^6(x)}{sin^3(x) \ * \ cos^3\left(x)}[/tex]

[tex]\sf \Longrightarrow \sf \int _{\pi }^{2\pi }\:\dfrac{sin^6\left(x\right)}{sin^3\left(x\right)\cdot \:cos^3\left(x\right)} +\dfrac{cos^6\left(x\right)}{sin^3\left(x\right)\cdot \:cos^3\left(x\right)}[/tex]

[tex]\Longrightarrow \sf \int _{\pi }^{2\pi }\:\dfrac{sin^3\left(x\right)}{\:cos^3\left(x\right)} +\dfrac{cos^3\left(x\right)}{sin^3\left(x\right)}[/tex]

                                                               

[tex]\Longrightarrow \sf \int _{\pi }^{2\pi }\ tan^3(x)+ cot^3(x)[/tex]

[tex]\sf \Longrightarrow \sf \int _{\pi }^{2\pi } \tan ^3(x)dx+\int _{\pi }^{2\pi } \cot ^3 (x)dx[/tex]

[tex]\Longrightarrow \sf \bold{ [ }-\ln |\sec \left(x\right) |+\dfrac{\sec ^2(x)}{2}-\dfrac{\cot ^2 (x)}{2}-\ln |\sin(x)| \bold{ ] }^{2\pi }_\pi[/tex]

apply limits

[tex]\sf \Longrightarrow \sf -\ln \left|\sec \left(2\pi \right)\right|+\dfrac{\sec ^2\left(2\pi\right)}{2}-\dfrac{\cot ^2\left(2\pi\right)}{2}-\ln \left|\sin \left(2\pi\right)\right|-(-\ln \left|\sec \left(\pi \right)\right|+\dfrac{\sec ^2\left(\pi\right)}{2}-\dfrac{\cot ^2\left(\pi\right)}{2}-\ln \left|\sin \left(\pi\right)\right|)[/tex]

simplify using trigonometric basic functions

[tex]\Longrightarrow \sf -\ln \left|\dfrac{1}{\cos \left(2\pi \right)}\right|+\dfrac{\left(\dfrac{1}{\cos \left(2\pi \right)}\right)^2}{2}-\dfrac{\cot ^2\left(2\pi \right)}{2}-\ln \left|\sin \left(2\pi \right)\right|- ( -\ln \left|\dfrac{1}{\cos \left(\pi \right)}\right|+\dfrac{\left(\frac{1}{\cos \left(\pi \right)}\right)^2}{2}-\dfrac{\cot ^2\left(\pi \right)}{2}-\ln \left|\sin \left(\pi \right)\right|)[/tex]

The value of cot(2π) is not defined. [ cot(2π) = ∞ ]

⇒  Undefined

Answer:

[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \boxed{\text{un} \text{de} \text{f}}[/tex]

General Formulas and Concepts:
Calculus

Differentiation

DerivativesDerivative Notation

Integration

Integrals

Integration Rule [Reverse Power Rule]:
[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:
[tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:
[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:
[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Methods: U-Substitution + U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx[/tex]

Step 2: Integrate Pt. 1

[Integrand] Rewrite:
[tex]\displaystyle \frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x} = \frac{\sin^6 x}{\sin^3 x \cos^3 x} + \frac{\cos^6 x}{\sin^3 x \cos^3 x}[/tex][Integrand] Simplify:
[tex]\displaystyle \frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x} = \tan^3 x + \cot^3 x[/tex][Integrand] Rewrite:
[tex]\displaystyle \frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x} = \tan x (\sec^2 x - 1) + \cot x (\csc^2 x - 1)[/tex]


Step 3: Integrate Pt. 2

[Integral] Rewrite:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{2 \pi}_{\pi} {\tan x (\sec^2 x - 1) + \cot x (\csc^2 x - 1)} \, dx[/tex][Integral] Rewrite [Integration Property - Addition/Subtraction]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{2 \pi}_{\pi} {\tan x (\sec^2 x - 1)} \, dx + \int\limits^{2 \pi}_{\pi} {\cot x (\csc^2 x - 1)} \, dx[/tex]

Step 4: Integrate Pt. 3

Identify variables for u-solve.

1st Integral

Set u:
[tex]\displaystyle u = \sec x[/tex][u] Apply Trigonometric Differentiation:
[tex]\displaystyle du = \sec x \tan x \, dx[/tex][du] Rewrite:
[tex]\displaystyle dx = \frac{1}{\sec x \tan x} \, du[/tex]

2nd Integral

Set v:
[tex]\displaystyle v = \csc x[/tex][v] Apply Trigonometric Differentiation:
[tex]\displaystyle dv = - \cot x \csc x \, dx[/tex][dv] Rewrite:
[tex]\displaystyle dx = \frac{-1}{\cot x \csc x} \, dv[/tex]

Step 5: Integrate Pt. 4

[Integrals] Apply Integration Method [U-Solve]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{x = 2 \pi}_{x = \pi} {\frac{\tan x (\sec^2 x - 1)}{\sec x \tan x}} \, du + \int\limits^{x = 2 \pi}_{x = \pi} {\frac{- \cot x (\csc^2 x - 1)}{\cot x \csc x}} \, dv[/tex][Integrals] Simplify:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{x = 2 \pi}_{x = \pi} {\frac{u^2 - 1}{u}} \, du - \int\limits^{x = 2 \pi}_{x = \pi} {\frac{v^2 - 1}{v}} \, dv[/tex][Integrals] Apply Integration Rule [Reverse Power Rule]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \frac{u^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \int\limits^{x = 2 \pi}_{x = \pi} {\frac{1}{u}} \, du - \Bigg( \frac{v^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \int\limits^{x = 2 \pi}_{x = \pi} {\frac{1}{v}} \, dv \Bigg)[/tex][Integrals] Apply Logarithmic Integration:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \frac{u^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \ln | u | \bigg| \limits^{x = 2 \pi}_{x = \pi} - \Bigg( \frac{v^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \ln | v | \bigg| \limits^{x = 2 \pi}_{x = \pi} \Bigg)[/tex]Back-Substitute variables u and v:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \frac{\sec^2 x}{2} \bigg| \limits^{2 \pi}_{\pi} - \ln | \sec x | \bigg| \limits^{2 \pi}_{\pi} - \Bigg( \frac{\csc^2 x}{2} \bigg| \limits^{2 \pi}_{\pi} - \ln | \csc x | \bigg| \limits^{2 \pi}_{\pi} \Bigg)[/tex]Simplify:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \bigg( \ln | \csc x | - \ln | \sec x | + \frac{\sec^2 x - \csc^2 x}{2} \bigg) \bigg| \limits^{2 \pi}_{\pi}[/tex]Apply Integration Rule [Fundamental Theorem of Calculus 1]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \boxed{\text{un} \text{de} \text{f}}[/tex]

∴ we have found the value of the given integral.

---

Learn more about integration: https://brainly.com/question/14413972

Learn more about calculus: https://brainly.com/question/20197752

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration


x/-6-8> -12

PLEASE HELP AND SOLVE

Answers

Answer:

24

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

x=24

I need help please, Its for today

Answers

Answer:

a) 1,2; 3.4

b) <1=<6, <6+<6+72=180, 2<6=108, <6=54.

<1=54

You can tell this by "these are parallel lines"

1. Find the equation of a line passing through the points (1,-2) and (-3,10).​

Answers

Answer:

Step-by-step explanation:

(1 , -2)   x₁ =1 & y₁ = -2

(-3,10)  x₂= -3 & y₂ = 10

First we need to find the slope.

[tex]\boxed{Slope = $\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$}[/tex][tex]\boxed{Slope=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}[/tex]

          [tex]=\dfrac{10-[-2]}{-3-1}\\\\\\=\dfrac{10+2}{-4}\\\\\\=\dfrac{12}{-4}\\\\\\= - 3[/tex]

m = -3

Equation of the line: y = mx + b

y = -3x + b

To find the value of b, take one of the point and substitue in the above equaiton.

(1 , -2)

-2 = -3*1 + b

-2 = -3 + b

-2 + 3 = b

b = 1

Equation of the line:

y = -3x + 1

help!
this is urgent
i need it rn
ty in advance

Answers

Answer:

The graph shows a steady declining plot as the aveage traffic volume increases. Since y axis is speed the correct answer is that as traffic volume increases the average vehicle speed decreases.

Step-by-step explanation:

(-4,9), (8,-7)
The endpoints of a diameter of a circle are given. Write the standard equation of the circle.

Answers

Answer:

(x-2)^2+(y-1)^2 = 10^2

(x-2)^2+(y-1)^2 = 100

Step-by-step explanation:

distance between points is diameter

x^2=  (8--4)^2+(-7-9)^2

x^2=12^2+16^2

x^2=144+256

x^2=400

diameter x=20 so radius =10

center point =midpoint (-4+8)/2 and (-7+9)/2

center point =(2,1)

(x-2)^2+(y-1)^2 = 10^2

(x-2)^2+(y-1)^2 = 100

Can anyone please solve this? I need it to be right.

Answers

Answer:

65

Step-by-step explanation:

[tex]\frac{3(2^5)-13(-2)+2^3}{-2^2+3^2-3} =\frac{3(32)+26+(8)}{(-4)+(9)-3} =\frac{96+34}{2} =\frac{130}{2}=65[/tex]

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