5. Find the volume of the composite space figure to the nearest whole number. (1 point)
6 mm
9 mm
11 mum
Not drawn to scale
0416 mm³
0705 mm³
01.294 mm³
0944 mm³

Answer:

0.3386 = 0.339 (rounded).

Step-by-step explanation:

It is the binomial type probability distribution.

The number of trial n= 3; the probability of the success trial is  0.16,  and the number of success trial k = 1.

Volume of a Rectangular Prism = length x width x height

Length = 4

Width = 2

Height = a

Volume = 7.2

7.2 = 4 x 2 x a

7.2 = 8 x a

a = 0.9

Answer: a = 0.9

Hope this helps!

Answer:

a = 0.9 cm

Step-by-step explanation:

Volume of a rectangular prism: L*W*H

Substitute the values above into the formula:

V = L*W*H

7.2 = 4*2*a

7.2 = 8a

/8     /8

0.9 = a

Therefore, the value of a is 0.9 cm.

Hope this helps!

Step-by-step explanation:

6x-12=x+3

6x-x=3+12

5x=15

x=15/5

x=3

Answer:

Step-by-step explanation:

What is value of m in the equation

3 (2x - 4) = x +3​?

3 (2x - 4) = x + 3​

6x - 12 = x + 3

5x = 15

x = 15 : 5

x = 3

Answer:

42 ft ^ 2

Step-by-step explanation:

All we have to do is multiply 14 and 3. That gives us 42.

Answer:

3/4 sq ft

Step-by-step explanation:

1/4*3=3/4

im pretty sure u meant 1/4 not 14 bc it says "mixed number"

Answer:

A, 3

Step-by-step explanation:

Just look at x axis, find 6, and then start going up until you hit the line. Then record the point you hit.

Answer:

B) - 6 + 3i

Step-by-step explanation:

   Complex number notation:

i² = -1

[tex]\sf \sqrt{-9}-6=\sqrt{3^2*i^2}-6[/tex]

               [tex]\sf = 3i - 6[/tex]

Answer:

3 m

Step-by-step explanation:

[tex]\textsf{Volume of a cone}=\sf \dfrac{1}{3} b h \quad\textsf{(where b is the area of the circular base and h is the height)}[/tex]

Given:

[tex]\implies \sf 10=\dfrac{1}{3} \cdot 10 \cdot h[/tex]

[tex]\implies \sf 10=\dfrac{10}{3}h[/tex]

[tex]\implies \sf 30=10h[/tex]

[tex]\implies \sf h=\dfrac{30}{10}=3[/tex]

Answer:

height: 3 meter

Explanation:

[tex]\sf volume : \frac{1}{3} \ x \ base \ area \ x \ height[/tex]

Here given:

Solve:

[tex]\longrightarrow \sf 10 = \frac{1}{3} \ x \ 10 \ x \ h[/tex]

[tex]\longrightarrow \sf 10 = \frac{10}{3} \ x \ h[/tex]

[tex]\longrightarrow \sf \frac{10 \ x \ 3}{10} = h[/tex]

[tex]\longrightarrow \sf 3 = h[/tex]

Answer:

35.66

Step-by-step explanation:

Don't work with the mean given at first

1. Multiply the mean of class A by the number of students in class A

35 times 15=525

2. Multiply the mean of class B by the number of pupils in class B

36 times 29=1044

3. Add the answers you got

1044+525

4.Add the pupils of both classes

29+15=44

5.Then divide the total grades and pupils

1569/44 =35.659

6 Then round off

=35.66

The value of two arithmetic means which are inserted between 3 and 24 are 24/9 and 75/9.

Arithmetic mean is the mean or average which is equal to the ratio of sum of all the group numbers to the total numbers.  

The two arithmetic means between 3 and 24 are has to be inserted.

3, A₂, A₃, 24

All the four numbers are in arithmetic progression. The nth terms of AM can be found using the following formula:

t(n)=a(n-1)d

Here, d is the common difference a is the first terms and n is the total term.  The first term, a=3 and t₄=24. Thus, the common difference is;

[tex]t(n)=a(n-1)d\\t(4)=3(4-1)d\\24=3(3)d\\24=9d\\d=\dfrac{24}{9}[/tex]

The second and 3rd term are:

[tex]A₂=3+\dfrac{24}{9}=\dfrac{51}{9}\\ A₃=\dfrac{51}{9}+\dfrac{24}{9}=\dfrac{75}{9}[/tex]

Thus, the value of two arithmetic means which are inserted between 3 and 24 are 24/9 and 75/9.

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The density of the material that this figurine was made from in pounds/inch³ is 0.183 lb/in³

To answer the question, we need to know what density is

Density is the mass per unit volume of a material.

It is given by ρ = m/v where

Now, given that the toy is dropped into a basin filled with water and found to displace 125.4 mL of water. It's volume is v = 125.4 mL

= 125.4 × 1 mL

= 125.4 × 0.0610237 in³

= 7.65237198 in³

Also, given that the figurine is then put on a scale and found to be 1.4 pounds in weight. It's mass is m = 1.4 lb

So, the density of the material ρ = m/v

ρ = 1.4 lb/7.65237198 in³

ρ =  0.183 lb/in³

So, the density of the material that this figurine was made from in pounds/inch³ is 0.183 lb/in³

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Answer:

the independent variable is s

the dependent one is m

hope this helps <3

Answer:

60/13

Step-by-step explanation:

Answer:

Algebra is simple and the answer is infinity due to there being over one million diffrent possoblitlitys, We know that because of albert ienstine so the answer has been solved.

Step-by-step explanation:

When you use word processor functions such as spell check and thesaurus to write a second draft, you are "C. Revising."

Revising means making changes and improvements to a piece of writing to make it better. This includes making it easier to understand, organizing it well, and making sure it is good quality overall.

Using spell check helps you fix mistakes in your spelling, while using the thesaurus helps you find different words that mean the same thing and choose better words to make your writing clearer and more accurate.

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Answer:

f(x) = 8x^6 + 1

Step-by-step explanation:

We want to examine which polynomial function grows larger and larger as the negative variable rises. We'll see that option d is correct: f(x) = 8x6 + 1

There are two things to keep in mind here.

The polynomial grows quicker as the exponent increases.

When a negative integer is evaluated with an even exponent, the result is always positive.

Then all the polynomials with an even leading exponent become larger and larger as x grows in the negative direction, especially the one with the biggest leading exponent, which is:

radius= 10 m

the area of the given circle.

[tex]a = \pi {r}^{2} [/tex]

[tex]a = \pi \times {10}^{2} [/tex]

[tex]a = 314.15927 \: {m}^{2} [/tex]

[tex]a = 314 \: {m}^{2} [/tex]

therefore, the area of the given circle is 314 square meters.

[tex]\large\boxed{Formula: a= \pi{r}^{2}}[/tex]

In this question raduis is given so we'll simply have to solve.

Let's solve!

The area of a circle is π times the radius squared.

Substitute the values according to the formula.

[tex]a= \pi \times {10}^{2}[/tex]

[tex]a= 314.1592654 \: {m}^{2}[/tex]

Now, we can round off to the nearest whole number.

The value in tenths place is less than 5 so we won't have to round up.

Final answer:

[tex]\large\boxed{a= 314 \: {m}^{2}}[/tex]

Hence, the area of the circle given in the question is 314 square inches to the nearest whole number.

Answer:

The answer should be $1127.74

Answer:

True, (-∞, ∞)           0 > -12

Step-by-step explanation:

8 > −4

8 - 8 > −4 - 8

0 > -12

Hope it helps :)

If you have any questions or anymore help lmk, happy to help with any school work!!

Have a nice day, you’ll make it thru :)

(shhhh i added your deleted question to this one as well, Image below)

The true correct statements about the box-and-whiskers plot are:

In a box-and-whiskers plot, the interquartile range (IQR) is a measure of the spread of the data which shows the variability of the data.

Median of a data is the value at the point where the vertical line divides the rectangular box.

Median for Group A is between: 45 and 50

Median time for Group B is: 40.

Therefore, the three statements are:

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Step-by-step explanation:

oh, come on ! one is finding the inequality itself, the other is solving it. you don't know the difference of that ?

if so, please let me know, what you don't understand of the following explanations, so that I can add whatever is necessary.

you know, what an equality (ahem, equation) is ?

both, equations and inequalities are like a balancing scale with usual different things on the two pans left and right.

an equation is when both sides are in balance. their weight is equal.

an inequality is, when one side is heavier than the other.

and you know, what a variable is ? it is a kind of placeholder for actual values. it is like keeping some space open on the scale pan with a list of conditions for what kind of things you can put in that open space, so that the status of the scale stays unchanged.

A

twenty less than a number is at least 15

looks mathematically

x - 20 >= 15 (larger or equal = "at least")

B

x - 20 >= 15

x >= 35

so, this is true for

{x € R | x >= 35}

or

{x € R | x = 35 or x > 35}

so, this is true for all real values of x that are at least 35.

Step-by-step explanation:

ask me if you don't understand

Answer:

B. AA similarity postulate

The codomain of the function [tex]g(x) = 2x^2 + 4x - 1[/tex] is [tex]g(x) = 2x^2 + 4x - 1[/tex]

The equation of the function is given as:

[tex]g(x) = 2x^2 + 4x - 1[/tex]

The above function is a quadratic function and it has the following features:

Domain = [tex](-\infty, \infty)[/tex]

Range: [tex][-3, \infty)[/tex]

When the range and the domain are combined, we have:

[tex][-3, \infty)\ and\ (-\infty, \infty)[/tex]

This gives

[tex][-3, \infty[[/tex]

Hence, the codomain of the function [tex]g(x) = 2x^2 + 4x - 1[/tex] is [tex]g(x) = 2x^2 + 4x - 1[/tex]

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Answer:

3 ¹³/²⁰ m

Step-by-step explanation:

You first take 8¼ m then you subtract 4⅗m giving you 3 ¹³/20

Answer:

7/8 (seven eighths)

Step-by-step explanation:

add the numerators (top numbers) together, to get 7. Leave the denominator (bottom number) alone, since they are the same. Think about it like you're adding two different parts of a whole.

you should get 7/8

hope this helps

Answer:

-2

Step-by-step explanation:

Find two points which lie on the line :

Formula for slope (m) :

Answer: [tex]-2[/tex]

Step-by-step explanation:

[tex]Slope:m=0[/tex]

[tex]y=mx+b[/tex]

[tex]-2*10^0[/tex]

[tex]-2~is~a~rational~number[/tex]

[tex]\frac{180}{pi}[/tex]°

Answer: X = 12

Step-by-step explanation: