4 - 5 5g > 39

What is the solution set for the inequality?

Answer:

  8

Step-by-step explanation:

After saving 1/3 of 6 dozen for the bake sale, the girls had 2/3 of 6 dozen left to split between them. Each of the 6 girls would receive 2/3 of 1 dozen, or 12×2/3 = 8 cupcakes.

5/6 girls have either blue or brown eyes. Since 2/9=4/18

And 11/18 + 4/18 = 15/18

You can simplify 15/18 to 5/6

596/1000 and 59.6%

Step-by-step explanation:

because when we make 596/1000 is 0.596

Answer: n=-3 and n=3/2

Step-by-step explanation:

To solve the expression, we want to find the values of n. Since there are no common factors in 2, 3, -9, we directly multiply the "a" and "c" values.

2×(-9)=-18

This means, we want to find two numbers that multiply to -18 and adds to 3. This can also be known as the cross method.

We will find that 6 and -3 multiply to -18, and adds to 3.

In our box method, we want to find the common factors.

|2n²|6n|

|-3n|-9|

Note: Just pretend the lines line up and form a square box, with a term in each box.

After finding that is in common between the boxes, we get (n+3)(2n-3)=0

To solve, we set each factor equal to 0.

n+3=0

n=-3

2n-3=0

2n=3

n=3/2

Answer:

It's A

Step-by-step explanation:

y/x

it's starting point is 5 and it goes up 1 and over 2

1 is on the y-axis and 2 is on the x-axis and it is y over x so the answer is 1/2x+5

NOTE:I MAY NOT BE ACCURATE BUT IM PROBABLY IT COULD BE WRONG BUT IF U REALLY ARE STUCK ON A QUESTION THEN CHOOSE A

Answer:

$38696.84

Step-by-step explanation:

7% interest

so *1.07 per year

10,000*1.07^x=y

10,000*1.07^20=$38696.84

The equation that represent the  value of Alizeh’s investment after 20 years is y = 1000(b)^20

The increase in the amount of his money can be represented using the exponential function as shown:

y = ab^x

Given the following

a = 1000

x = 20 years

Substitute

y = 1000(b)^20

Hence the equation that represent the  value of Alizeh’s investment after 20 years is y = 1000(b)^20

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the answer is B, D and F. I hope this was helpful

Answer:

it is the answer on the top

Answer:

V = 19329.14 cubic inches

Step-by-step explanation:

Volume of cylinder

[tex]V = \text{area of circle} \times \text{height}\\V = \pi r^2 \times h[/tex]

r ... radius of circle
h ... height of cylinder

Given information:

r = 18 in

h = 19 in

Now let's substitute the values in formula.

[tex]V = \pi r^2 \times h \\V = \pi (18)^2 \times 19\\V = 6156\pi\\V = 6156 \times 3.14\\V = 19329.84 \text{ in}^2[/tex]

Answer:

I think it's

G: 71

H: 109

K: 151

M: 29

Step-by-step explanation:

This shows many straight angles, which we can use to find the answers.

H and 71 are on one, every right angle is 180 degrees, so we subtract 71 from 180 and get 109. G and 71 are vertical angles which makes them the same, therefore G is also 61.

M and 151 are on another straight angle, so we do the same thing, subtract 151 from 180 and we get 29. There is a line under that and M and the little unmarked angle are vertical angles so they are the same making the little one 29, making K also 151.

Hope this helps

The meters of fencing that is needed is = 3.36m

The garden is designed in a trapezoid form with sides= a; 3.3m and b; 5.28m.

The area of the trapezoid garden = 13.92 m²

Therefore the meters of fencing needed which is height = ?

The formula for the area of trapezoid = A = (a+b/2)h

From the formula make h the subject of formula;

h = A *2/a+b

h = 13.92*2/3.3+5.28

h =27.84/8.28

h= 3.36m

Therefore, the meters of fencing that is needed is = 3.36m.

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Answer:

19.00 x h + 25.00 =

What you make in a day if you work for h hours.

Step-by-step explanation:

You automatically make $25.00 when you show up.

So the equation is asking for how many hours. If you get $19 per hour

then it would be $19.00 x h (how many hours you worked) + $25.00.

Example:

If you worked for 5 hours and one day, then the equation would be

19.00 x 5= 95

95 + 25 (for showing up that day) = 120

So if you worked 5 hours for one day you would make 120

(This was just an example to further explain how the equation worked)

Hope this helped!

Have a great day!!

Answer:

it’s 3 because chinese had the era.

Step-by-step explanation:

The volume of the pyramid is the amount of space in it, and the volume of the pyramid is 403.33 mm³

The given parameters are:

The volume of a pyramid is:

Volume = 1/3 * Base area * Height

So, we have:

Volume = 1/3 * 110 * 11

Evaluate

Volume = 403.33

Hence, the volume of the pyramid is 403.33 mm³

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Answer: y = 1/2x + 1/2

The categories that the expenses best fit into are:

fixed expenses :

variable expenses:

Fixed expenses are the expenses that are constant. They do not vary with the quantity bought. Variable expenses are the expenses that vary. More quantities can be bought and this increases the expenses.

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Answer:

5

Step-by-step explanation:

It's in the middle of all the numbers

If you do need a more in-depth explanation just comment under here and I'd be happy to show you how I did it :)

The best estimate of the profit when 350 pounds of food are produced is $5300

The quadratic regression is given as:

[tex]f(x) = -0.0817x^2 + 102.24x - 20421[/tex]

When 350 pounds are produced, it means that:

x = 350.

So, we have:

f(350) = -0.0817(350)^2 + 102.24(350) - 20421

Evaluate

f(350) = 5354.75

Approximate

f(350) = 5300

Hence, the best estimate is $5300

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The action to choose two among the seven seniors to be cocaptains is a combination and there are 21 different choices.

The major difference between permutation and Combination lies in the fact that the different ways of arranging a set of objects into a sequential order are termed as Permutation while one of the several ways of choosing items from a large set of objects, without considering an order is termed as Combination.

On this note, the action is a combination and the number of ways is; 7!/5!2! = 21.

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Given,

ABCD is a cyclic quadrilateral in which AC and BD are its diagonals.

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \sf∠DBC= 55° and ∠BAC = 45°[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \sf∠CAD = ∠DBC= 55° (Angles \: in \: the \: same \: segment)[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

Thus,

[tex] \sf∠DAB=∠CAD + ∠BAC[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \sf= 55° + 45° [/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \sf= 100°[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

We know that the opposite angles of a cyclic quadrilateral are supplimentary.

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \sf ∠DAB +∠BCD = 180°[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \sf∠BCD = 180°-100° =80°[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \:[/tex]

[tex] \pink{\boxed{\sf{∠BCD = 80°}}}[/tex]

Answer:

∠BCD = 80°

Step-by-step explanation:

ABCD is a cyclic Quadrilateral.

∠DBC = 55°

∠BAC = 45°

∠BDC

=> ∠BAC = ∠BDC

=> 45° = ∠BAC { Angles of same segment BC}

In Triangle BCD

=> ∠BDC + ∠DBS + ∠BCD = 180°

=> 45° + 55° + ∠BCD = 180°

=> 100° + ∠BDC = 180°

=> ∠BDC = 180-100

=> 80° ans.

Answer:

Volume of Cone=1/3πd²/4×h

= 1/3π×7²/4×9

= 36.75cm³

[tex]\large\displaystyle\text{$\begin{gathered}\sf 1) \ \left\{\begin{matrix} 5x-3y-z=1&\\ x+4y-6z=-1& \\ 2x+3y+4z=9& \end{matrix}\right. \end{gathered}$}[/tex]

The coefficient matrix associated with the system is constructed and the columns and rows are reduced.

                [tex]\left ( \begin{array}{ccc|c} 5 & -3 &-1 &1\\ 1 & 4 & -6 &-1\\ 2 & 3 & 4 & 9 \end{array} \right ) \begin{array}{c} \xrightarrow[\textup{F}_3- 2\textup{F}_2]{\textup{F}_1 - 5\textup{F}_2} \end{array} \left ( \begin{array}{ccc|c} 0 & -23& 29 &6\\ 1 & 4& -6 &-1\\ 0 & -5 &16 & 11 \end{array} \right )\\ \ \\ \ \\ \begin{array}{c} \xrightarrow[]{23\textup{F}_3 - 5\textup{F}_1} \end{array} \left ( \begin{array}{ccc|c} 0 & -23& 29 &6\\ 1 & 4& -6 &-1\\ 0 & 0 & 223 & 223 \end{array} \right )[/tex]

So, z=1. Translating the last matrix to the associated system of equations, we have that x=1, y=1, since:

                                       [tex]\large\displaystyle\text{$\begin{gathered}\sf \begin{align*} y&=\dfrac{6-29}{-23}=\dfrac{-23}{-23}=1\\ x = -1+6-4=1 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{2) \ \left\{\begin{matrix} x+y=7& \\ x\times y=12& \end{matrix}\right. } \end{gathered}$}[/tex]

Clear an unknown in the first equation and substitute the resulting expression in the second. Next, the quadratic equation is solved.

             [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ y=7-x \quad \Longrightarrow \quad 12=x(7-x)=7x-x^2 } \end{gathered}$}[/tex]

                    [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ 0=x^2-7x+12=(x-4)(x-3); } \end{gathered}$}[/tex]

                [tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{ x_1=4\qquad x_2=3 \Longrightarrow y_1=3 \qquad y_2=4 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{3) \ \left\{\begin{matrix} x^2+y^2=169& \\ x+y=17& \end{matrix}\right. } \end{gathered}$}[/tex]

Clear an unknown in the first equation and substitute the resulting expression in the second. Next, the quadratic equation is solved.

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{ y=17-x \quad \Longrightarrow \quad 169=x^2 +(17-x)^2=x^2+x^2 -34x+289 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{ 0=2x^2-34x+120=2(x^2-17+60)=2(x-12)(x-5); } \end{gathered}$}[/tex]

               [tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{ x_1=4\qquad x_2=3 \Longrightarrow y_1=3 \qquad y_2=4 } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{4 \ \left\{\begin{matrix} y^2-2y+1=x & \\ \sqrt{x}+y=5 & \end{matrix}\right. } \end{gathered}$}[/tex]

Substitute the expression that represents x into the second equation. Then both sides of the equation are squared and solved.

   [tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{ \sqrt{y^2-2y+1}+y=5\quad \Longrightarrow\quad \left ( \sqrt{y^2-2y+1} \right )^2=(5-y)^2 } \end{gathered}$}[/tex]

                  [tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{ y^2-2y+1=y^2-10y+25\quad \Longrightarrow\quad 8y=24; } \end{gathered}$}[/tex]

                                     [tex]\large\displaystyle\text{$\begin{gathered}\sf \pmb{ y=6 \qquad x=4 } \end{gathered}$}[/tex]

Answer:

1. How many pupils does Mrs.Anub have in all

I am sorry but I could only solve question 1

Step-by-step explanation:

Answer:

Step-by-step explanation:

a. How many pupils does she have in the class?

b. 40 pupils failed in the test.

c.  x = all pupil in the class

    percentage

d.   75/100 x = 40

e.   75/100 x = 40

           x        = 40*100/75

                     =  53.33

        pupils   =   53 people

f. There are 53 pupils in the class.

Answer:

Given the equations, I plotted 2 lines.

Line 1               Line 2

 x  |  y                x  |  y  

 0  | 101             0  |  -5

  1  |  101             1  |  -6

Answer:

Option (D): f(x) = 2x^2 – 3

Step-by-step explanation:

Math.

The function that represents the data in the table is y=2x²-3

A relation is a function if it has only One y-value for each x-value.

Let us check the function of the given data by plugging any ordered pair in the given functions

Let us take a point (1, -1) to check each function

(a) y=x/2-3

-1= 1/2-3

-1=-5/2

So y=x/2-3 is not the function

(b) y=2ˣ-3

-1=2-3

-1=-1

Now let us check for other point

5=4-3

5=1

This function is not satisfied for all points

(c) y=2x-3

-1=-1

For point (2, 5)

5=-1

This function is not satisfied for all points

(d) y=2x²-3

-1=2-3

-1=-1

Now 5=8-3

5=5

Hence, the function that represents the data in the table is y=2x²-3

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Answer:

7

Step-by-step explanation:

The median is 7, if you place all the numbers in order then start crossing off the smallest and then largest number, you would be left with the number in the middle which is 7.

Answer:

7

Step-by-step explanation:

3, 3, 5, 7, 8, 9, 11

7 is in the middle.

answer : 9.5 because you subtract and then divide by 2