3ª = 69


Help pleaseeee it’s solving exponential equations with logarithms worksheet

Step-by-step explanation:

a = -2

b = 3

c = 5

[tex]3ac - a + 2b[/tex]

= Solution,

= 3 ( - 2 ) × 5 - ( - 2 ) + 2 × 3

here ... ( + ) × ( - ) = ( - )

= - 6 × 5 - ( - 2 ) + 2 × 3

here .... ( - ) × ( - ) = ( + )

= - 6 × 5 + 2 + 2 × 3

= - 30 + 2 + 6

= - 30 + 8

here the ( - ) have greater variable so...

= - 22

hence - 22 is the answer . ....

The solution -1 is an extraneous solution

Neither -1 nor -6 is a true solution to the equation.

Option D is the correct answer.

Solutions are the values of an equation where the values are substituted in the variables of the equation and make the equality in the equation true.

We also find the solution in a system of equations using the substitution or elimination method.

Example:

2x + 4 = 8

The solution is x = 2.

We have,

To solve the equation x + 4 = √(x + 10), we need to isolate the radical term on one side of the equation and then square both sides to eliminate the radical.

Here are the steps:

x + 4 = √(x + 10)

Subtract 4 from both sides:

x = √(x + 10) - 4

Square both sides:

x² = (√(x + 10) - 4)²

Expand the right side using the formula (a - b)^2 = a^2 - 2ab + b^2:

x² = x + 6 - 8√(x + 10)

Move all terms to the left side:

x² - x - 6 + 8√(x + 10) = 0

To solve this equation, we can use a substitution u = √(x + 10):

u = √(x + 10)

Square both sides:

u² = x + 10

Substitute into the original equation:

(u² - 10) + 4 = u

Simplify:

u² - u - 6 = 0

Factor:

(u - 3)(u + 2) = 0

So u = 3 or u = -2.

But u = -2 leads to a negative value under the square root in the substitution u = √(x + 10), which is not allowed.

Therefore, we only consider u = 3, which gives:

√(x + 10) = 3

Square both sides:

x + 10 = 9

Subtract 10 from both sides:

x = -1

So the solution to the original equation is x = -1.

To check if it is extraneous, we need to substitute it back into the original equation:

x + 4 = √(x + 10)

-1 + 4 = √(-1 + 10)

3 = √9

3 = 3

The equation is true, so x = -1 is a valid solution and not extraneous.

Therefore,

Neither -1 nor -6 is a true solution to the equation.

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Answer: i think is b

Step-by-step explanation: because I do read lesson so I guess I think is b that why.

Answer:

6

Step-by-step explanation:

Answer:

The price for ounce is: $0.25 and she bought 16 ounces of straberris

Step-by-step explanation:

If you have 16 ounces and its 4 dollars you do 4/16 to get 0.25

Answer:

26 cm

Step-by-step explanation:

Formula for Perimeter

Solving (given Perimeter is 84 cm and width is 16 cm)

Answer:

L= 26cm

Step-by-step explanation:

Perimeter= 2(l x w)

Perimeter= 84cm

Width= 16cm

Length=?

84= 2l + 32

2l = 84-32

2l= 52

L= 52/2

L= 26cm

Speed^2 or velocity^2 because 12x12=144

It's looks like the Kinetic energy equation:

KE = 1/2mv^2

Hope this helps!

From the figure given above, angel < ABE = 40°

The angle of a straight line = 180°

That is angle <ABC = 180°

If <EBC is = 140°

Therefore, <ABE = 180 - 140

= 40°

Therefore, from the figure given above, angel < ABE = 40°

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Answer:

21 minutes

Step-by-step explanation:

hope it helps you

Answer:

In Exercises 9 − 16, Ind the indicated measure in a LMNQ. Explain your reasoning. m ∠ L M N Answer m ∠ L M N = 80 ∘ View Answer Discussion You must be signed in to discuss. AS Ahin S. February 11, 2021 Find m?LMN in parallelogram LMNQ AS Ahin S. February 11, 2021 Watch More Solved Questions in Chapter 7 Problem 1 Problem 2 Problem 3 Problem 4

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Continuous compounding is the potentially endless number of periods in which compound interest may be calculated. The worth of the investment after a period of 10 years will be $850.34.

Continuous compounding is the potentially endless number of periods in which compound interest may be calculated and reinvested into an account's balance.

[tex]\rm A = Pe^{rt}[/tex]

where,

A is the principal amount after t number of years,

r is the rate at which the principal is been compounded, and P is the principal amount.

Given the principal amount of $570 is invested for a period of 10 years, and at a rate of 4% per year, therefore, the worth of the investment after 10 years will be,

[tex]\rm A = \$570 \times e^{(0.04 \times 10)} = \$850.34[/tex]

Hence, the worth of the investment after a period of 10 years will be $850.34.

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Answer:

Angles around a point sum to 360°

⇒ ∠SPT + ∠TPU + 86° + 60° + 154° = 360°

⇒ ∠SPT + ∠TPU = 60°

Therefore:

∠SPQ clockwise = ∠SPT + ∠TPU + 86°

                            = 60° + 86°

                            = 146°

∠SPQ anticlockwise = 60° + 154°

                                  = 214°

Answer:

See below ~

Step-by-step explanation:

The total internal measure is 360°.

Finding ∠SPQ (clockwise):

Finding ∠SPQ (counterclockwise) :

Answer:

2πx3

Step-by-step explanation:

Answer:

1:1

Step-by-step explanation:

Answer:

B. 3.16

Step-by-step explanation:

1) formula of the required distance is:
[tex]d=\sqrt{(X_A-X_B)^2+(Y_A-Y_B)^2} ;[/tex]

2) if A(3;-8) and B(0;-9), then according to the formula above:

[tex]d=\sqrt{(0-3)^2+(-9+8)^2} =\sqrt{10}.[/tex]

d≈3.16

Step-by-step explanation:

how is that math ?

anyway,

*♡ = O

●* = H

arrow up and filed triangle = E

arrow down and 3/4 circle = R

Answer:

B

Step-by-step explanation:

since domain should be in positive i thinks this should be answer B

Answer:

left one on 3rd row

Step-by-step explanation:

using the rules of exponents/ radicals

[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]

[tex]a^{\frac{m}{n} }[/tex] = [tex]\sqrt[n]{a^{m} }[/tex]

given

[tex]12^{-\frac{4}{7} }[/tex]

= [tex]\frac{1}{12^{\frac{4}{7} } }[/tex]

= [tex]\frac{1}{\sqrt[7]{12^{4} } }[/tex]

The partial differential expression is equal to the expression 30 · x · (x³ + y⁴) + 36 · x² · y² · (y² + x²) and the total differential formula is Δz = (0.9 · x² + 0.6 · y²) · cos (x³ + y³).

In the first part of this question we must apply the concept of partial derivatives to find the form of the entire expression, whose variables are two. Partial differentiation is a generalization of the ordinary differentiation:

[tex]\frac{\partial f}{\partial x} = 6\cdot x^{5}+12\cdot x^{3}\cdot y^{4}+y^{6}[/tex]     (1)

[tex]\frac{\partial^{2} f}{\partial x^{2}} = 30\cdot x^{4}+36\cdot x^{2}\cdot y^{4}[/tex]     (2)

[tex]\frac{\partial^{2} f}{\partial x \,\partial y} = 48\cdot x^{3}\cdot y^{3}+6\cdot y^{5}[/tex]     (3)

[tex]\frac{\partial f}{\partial y} = 12\cdot x^{4}\cdot y^{3} +6\cdot x \cdot y^{5}[/tex]     (4)

[tex]\frac{\partial^{2} f}{\partial y^{2}} = 36\cdot x^{4}\cdot y^{2} + 30\cdot x\cdot y^{4}[/tex]     (5)

[tex]\frac{\partial f}{\partial y \,\partial x} = 48\cdot x^{3}\cdot y^{3}+6\cdot y^{5}[/tex]     (6)

Then, the entire expression is:

30 · x⁴ + 36 · x² · y⁴ + 36 · x⁴ · y² + 30 · x · y⁴

30 · (x⁴ + x · y⁴) + 36 · (x² · y⁴ + x⁴ · y²)

30 · x · (x³ + y⁴) + 36 · x² · y² · (y² + x²)

In the second part we must determine the total differential of z with respect to two variables:

[tex]\Delta z = \frac{\partial f}{\partial x}\cdot \Delta x + \frac{\partial f}{\partial y}\cdot \Delta y[/tex]     (7)

If we know that z = sin (x³ + y³), Δx = 0.3 and Δy = 0.2, then the total differential of the function is:

Δz = 3 · cos (x³ + y³) · x² · (0.3) + 3 · cos (x³ + y³) · y² · (0.2)

Δz = (0.9 · x² + 0.6 · y²) · cos (x³ + y³)

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Using the uniform distribution, it is found that there is a 0.3608 = 36.08% probability that the male will lose between 19.41 and 23.74 percent of their body weight.

It is a distribution with two bounds, a and b, in which each outcome is equally as likely.

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

In this problem, male black bears will typically drop between 17 to 29 percent of their body weight, hence the bounds are a = 17 and b = 29.

The probability that the male will lose between 19.41 and 23.74 percent of their body weight is given by:

[tex]P(19.41 \leq X \leq 23.74) = \frac{23.74 - 19.41}{29 - 17} = 0.3608[/tex]

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Step-by-step explanation:

Find the HCF of 9m 80cm 8m 40cm 4m 20cm

Answer:

Cot theta = 0.2

Step-by-step explanation:

[tex]180^\circ < \theta < 270^\circ[/tex]

So, theta is in the third quadrant

[tex]Cot \ \theta =\dfrac{1}{Tan \ \theta}\\[/tex]

         [tex]= \dfrac{1}{2}[/tex]

[tex]\sf Cot \ \theta = 0.5[/tex]

Answer:

End Behavior is

y -> -inf as x -> -inf
y -> -inf as x -> +inf

Step-by-step explanation:

I am not sure if your teacher has explained how to look at the equation and determine the end behavior of that function without a graph. Here is a picture that explains it.

[tex]\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}[/tex]

          what is the value of 7x-3y-1 for x = -2 and y = 4?

[tex]\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}[/tex]

Replace x with -2 and y with 4:-

[tex]\sf{7(-2)-3(4)-1}[/tex]

On simplification,

[tex]\sf{-14-12-1}[/tex]

On further simplification,

[tex]\sf{-27}[/tex]

[tex]\rule{300}{1}[/tex]

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

[tex](\stackrel{x_1}{-3}~,~\stackrel{y_1}{6})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{2}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{\cfrac{2}{5}}(x-\stackrel{x_1}{(-3)})\implies y-6=\cfrac{2}{5}(x+3)[/tex]

[tex]y-6=\cfrac{2}{5}x+\cfrac{6}{5}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{5}}{5(y-6)~~ = ~~5\left( \cfrac{2}{5}x+\cfrac{6}{5} \right)}\implies 5y-30~~ = ~~2x+6 \\\\\\ -2x+5y-30=6\implies -2x+5y=36\implies 2x-5y=-36[/tex]

answer is given below

29/6 = 203/42

16/7 = 96/42

to make the denominator 42 we use common tables for this just multiplying .

Answer:

the fractions are 203/42 and 96/42

Step-by-step explanation:

[tex]for \: \frac{29}{6} \\ \: multply \: the \: numerator \: and \: denominator \: by \: 7 \\ \frac{29}{6} \times \frac{7}{7} = \frac{203}{42} \\ for \: \frac{16}{7} also \: multiply \: the \: numerator \\ and \: denominatorby \: 6 \\ = \frac{16}{7} \times \frac{6}{6} = \frac{96}{42} [/tex]

Answer:

19.8 rounded to 20m

Step-by-step explanation:

reason;

Area=1/2 x perimeter x apothem

27=1/2 x p x 2.726

Divide both sides by 1/2

54= p x 2.726

Now divide both sides by 2.726 to isolate p

Answer p=19.8