3) A certain reaction has the following general form: A + B à AB At a particular temperature the concentration versus time were collected for this reaction, and a plot of ln[A]t versus time resulted in a straight line with a slope of −3.7 x 10−3 s−1. Show your math! (5 points) a. What is the order of the reaction? b. What is the rate constant (including units)? c. Calculate the half-life for the reaction. d. If the initial concentration of A is 0.250 M, what is the concentration after 220 seconds?

Answers

Answer 1

Answer:

a. First order.

b. [tex]k=3.7x10^{-3}s ^{-1}[/tex]

c. [tex]t_{1/2}=187.3s[/tex]

d. [tex][A]=0.111M[/tex]

Explanation:

Hello.

a. In this case since the slope is in s⁻¹ we can infer that the lineal form of the rate law is:

[tex]ln[A]=-kt+ln[A]_0[/tex]

Which is also:

[tex]y=mx+b[/tex]

It means that the reaction is first-order as slope equals the negative of the rate constant which also has units of first-oder reaction.

b. Since the slope is −3.7 x 10−3 s−1 the rate constant is:

[tex]k=-m\\\\k=-(-3.7x10^{-3}s ^{-1})\\\\k=3.7x10^{-3}s ^{-1}[/tex]

c. For first-order reactions, the half-life is:

[tex]t_{1/2}=\frac{ln(2)}{k}\\ \\t_{1/2}=\frac{ln(2)}{3.7x10^{-3}s^{-1}}\\\\t_{1/2}=187.3s[/tex]

d. In this case, since the integrated first-order rate law is:

[tex][A]=[A]_0exp(-kt)[/tex]

The concentration once 220 seconds have passed is:

[tex][A]=0.250Mexp(-3.7x10^{-3}s^{-1}*220s)\\\\[/tex]

[tex][A]=0.111M[/tex]

Regards.


Related Questions

Enter the symbol of a sodium ion, Na+
N
a
+
, followed by the formula of a sulfate ion, SO42−
S
O
4
2

. Separate the ions with a comma only—spaces are not allowed.
Express your answers as ions separated by a comma.

Answers

Answer:

Na⁺,SO₄²⁻

Explanation:

Sodium sulfate is formed by the sodium and sulfate ion.

Sodium is present in group one thus it has only one valence electron. Sodium lose its one valence electron to get complete octet and thus form cation with +1 charge.

On other hand sulfate ion is an anion it carries -2 charge so when it react with sodium there are two sodium atom combine with one sulfate ion inorder to make the compound neutral.

2Na + SO₄²⁻  →  Na₂SO₄

Sodium sulfate is actually form when sodium react with sulfuric acid and hydrogen gas is liberated.

Chemical equation:

Na + H₂SO₄  →  Na₂SO₄ + H₂

Balance chemical equation:

2Na + H₂SO₄  →  Na₂SO₄ + H₂

Match the term with the definition. (4 points)

Column A
1.
Liquid

:
Liquid

2.
Plasma

:
Plasma

3.
Solid

:
Solid

4.
Gas

:
Gas

Column B
a.
has lots of space between the charged particles

b.
has lots of space between particles and is easily compressible

c.
flows easily but is difficult to compress

d.
does not flow easily and is difficult to compress

Answers

Answer:

1 - does not flow easily and is difficult to compress

2 -does not flow easily and is difficult to compress.

3 -has lots of space between the charged particles.

4-flows easily but is difficult to compress.

Explanation:

How many electrons are located in the outermost orbit in the Bohr model of a boron atom?
A. 1
B. 2
C. 3
D. 4

Answers

It has to be c because That means there are 5 electrons in an boron atom. Looking at the bohr , you can see there are two electrons in shell one and three more in shell two.

According to the electronic configuration of boron, there are three electrons in the Bohr model of a boron atom.

What is electronic configuration?

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Ernest Rutherford and Henry
Moseley used this subatomic
particle to differentiate atoms by
their atomic number.

Answers

Answer:

electron

Explanation:

Four different methods are described for validating the results of a particular analysis. Indicate for each whether the method primarily checks the accuracy of the analysis or the precision of the analysis. Method 1: Five aliquots of the same sample are injected for a gas-chromatographic analysis by one person on the same day. a. precision.b. accuracy.Method 2: A known amount of analyte is added to an aliquot of the sample and analyzed with the sample. a. precision.b. accuracy. Method 3: Aliquots from a blood sample are sent to three separate laboratories for analysis using the same method. a. precision.b. accuracy. Method 4: Identical standards are analyzed by two different methods. a. accuracy.b. precision.

Answers

Answer:

Method 1 - precision

Method 2 - accuracy

Method 3 - precision

Method 4 - accuracy

Explanation:

The accuracy of a method refers to how close the experimental result is to the accepted value. Accuracy could be checked by carrying out the required test on the standard and not on the sample or by adding a known amount of analyte to the sample so that the results obtained can be carefully compared.

Precision on the other hand, refers to how close the results of a replicate analysis are to each other. In testing for precision, the analysis must be carried out several times, in order to check how close the results are to each other.

Ammonium cyanate (NH4CNO) reacts to form urea (NH2CONH2). at 65 degrees celsius, the rate constant, K is 3.60 L mol^-1 s^-1. what is the rate law for this reaction

Answers

Answer:

v = 3.60Lmol⁻¹s⁻¹ [NH₄CNO]²

Explanation:

The reaction at 65°C of ammonium cyanate to produce urea is:

NH₄CNO → NH₂CONH₂

The general rate law is:

v = K  [NH₄CNO]ˣ

Where v is rate of the reaction, K is rate constant and x represents the order of reaction

Based on the units of the rate constant (Lmol⁻¹s⁻¹ = M⁻¹s⁻¹) the reaction must be order 2 and the rate law:

v = K  [NH₄CNO]²

v = 3.60Lmol⁻¹s⁻¹ [NH₄CNO]²

In a chemical reaction, what happens to the total number of each type of atom?

Answers

Answer:

In a chemical reaction the total mass of all the substances taking part in the reaction remains the same. Also, the number of atoms in a reaction remains the same. Mass cannot be created or destroyed in a chemical reaction.

Stoichiometry must be multiplied by the number that is printed on the element's foot in order to determine how many atoms of a certain element there are in a given molecule.  Therefore, the quantity of atoms inside a reaction doesn't change.

What is atom?

Atom is the smallest particle of any element, molecule or compound. Atom can not be further divided. Atoms have a central nucleus and electrons that move in a fixed orbit around it. Protons and neutrons are found in the nucleus. Electron has -1 charge while proton has +1 charge.

The combined mass of all of the components involved in a chemical process stays constant. Additionally, the quantity of atoms inside a reaction doesn't change. Chemical reactions cannot produce or destroy mass.

Therefore, the quantity of atoms inside a reaction doesn't change.

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It takes 15.0 seconds to run 100.0 meters if you run .0500 how many meters will you run

Answers

Answer:

150 seconds

Explanation:

How many oxygen atoms are in 8.20 g Na 2SO 4?

Answers

Answer:

No. of atom =

no.of moles x avagardro's number xatomicity

= weight /molar mass x No x atomicity

=8.2/142 x6.02x10^23 x 4

=0.346 x 10^23(approximately)

Suppose 4.0 g of hydrogen reacts completely with 32.0 g of oxygen to form one product what is the mass of the product?

Answers

Answer: The mass of product, [tex]H_2O[/tex] is, 36.0 grams.

Explanation : Given,

Mass of [tex]H_2[/tex] = 4.0 g

Mass of [tex]O_2[/tex] = 32.0 g

Molar mass of [tex]H_2[/tex] = 2 g/mol

Molar mass of [tex]O_2[/tex] = 32 g/mol

First we have to calculate the moles of [tex]H_2[/tex] and [tex]O_2[/tex].

[tex]\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}[/tex]

[tex]\text{Moles of }H_2=\frac{4.0g}{2g/mol}=2.0mol[/tex]

and,

[tex]\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}[/tex]

[tex]\text{Moles of }O_2=\frac{32.0g}{32g/mol}=1.0mol[/tex]

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

[tex]2H_2+O_2\rightarrow 2H_2O[/tex]

From the balanced reaction we conclude that

2 mole of [tex]H_2[/tex] react with 1 mole of [tex]O_2[/tex]

From this we conclude that, there is no limiting and excess reagent.

Now we have to calculate the moles of [tex]H_2O[/tex]

From the reaction, we conclude that

2 moles of [tex]H_2[/tex] react to give 2 moles of [tex]H_2O[/tex]

Now we have to calculate the mass of [tex]H_2O[/tex]

[tex]\text{ Mass of }H_2O=\text{ Moles of }H_2O\times \text{ Molar mass of }H_2O[/tex]

Molar mass of [tex]H_2O[/tex] = 18 g/mole

[tex]\text{ Mass of }H_2O=(2.0moles)\times (18g/mole)=36.0g[/tex]

Therefore, the mass of product, [tex]H_2O[/tex] is, 36.0 grams.

Concentration data is commonly monitored during a reaction to determine the order with respect to a reactant. Consider the types of observations listed, and determine which order is likely for that reactant. Assume all other factors are held constant.
An increase in the concentration of the reactant in solution causes the reaction rate to increase exponentially.
Choose...first order, second order, zero order
The reaction rate increases in direct proportion to the concentration of the reactant in solution.
Choose...first order, second order, zero order
The reaction rate is constant regardless of the amount of reactant in solution.
Choose...first order, second order, zero order

Answers

Answer:

An increase in the concentration of the reactant in solution causes the reaction rate to increase exponentially - first order

The reaction rate increases in direct proportion to the concentration of the reactant in solution -second order

The reaction rate is constant regardless of the amount of reactant in solution - zero order

Explanation:

The Order of Reaction refers to the power dependence of the rate on the concentration of each reactant. The order of reaction is determined experimentally and not necessarily by inspection.

Typically, in a second order reaction, the rate of reaction increases in proportion to increase in concentration.

For a first order reaction, the rate of reaction increases exponentially as the increase in concentration.

For a zero order reaction, the rate of reaction is independent of the concentration of the reactant.

What atomic symbol completes this reaction?
ГРо
220
Po →
84
?
+
liei
O
224
Pb
82
04
2+
He
2
o
220
At
85
0 220
Rn
86

Answers

Answer:

Option C is correct = ₈₅At²²⁰

Explanation:

Given radioactive decay shows the beta emission.

²²⁰₈₄Po    ₈₅At²²⁰  +  ⁰₋₁e ⁻

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

Properties of beta radiations:

1) They can travel in air in few meter distance.

2) These radiations can penetrate into the human skin.

3) The mass of beta particle is smaller than the alpha particles.

4) The sheet of aluminium is used to block the beta radiation

¹⁴₆C → ¹⁴₇N + ⁰₋₁e ⁻

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

How much heat is required to raise the temperature of 93.5 gg of water from its melting point to its boiling point

Answers

Answer:

39270 J

Explanation:

The quantity of heat required to raise the temperature of a substance from its initial temperature to its final temperature is given by:

Q = mCΔT

m = mass of substance, C = specific heat capacity of substance, ΔT = temperature change = final temperature - initial temperature

Melting point = 0°C, boiling point = 100°C, m = 93.5 g = 0.0935 g, ΔT = boiling point - melting point = 100 - 0 = 100°C, C = 4200 J/kg°C

Q = mCΔT

Q = 0.0935 × 4200 × 100 = 39270 J

Select the correct responses to the questions from the drop-down menus.

Which type of precipitation freezes when it comes into contact with a cold surface?

Which type of precipitation is round pellets of ice more than 5 millimeters in diameter?

Which type of precipitation is water vapor that condenses into ice crystals in clouds?

Answers

Answer:

Which type of precipitation freezes when it comes into contact with a cold surface?  

✔ freezing rain

Which type of precipitation is round pellets of ice more than 5 millimeters in diameter?  

✔ hail

Which type of precipitation is water vapor that condenses into ice crystals in clouds?  

✔ snow

Explanation:

The type of precipitation that freezes when it comes into contact with a cold surface is freezing rain.

The type of precipitation that is round pellets of ice more than 5 millimeters in diameter is hail.

The type of precipitation where water vapor condenses into ice crystals in clouds is snow.

Freezing rain is the rain that is maintained at a temperature that's below freezing by ambient air mass. It's made entirely of liquid droplets.

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PLEASEEEEEEEEEEEEEEEEEEEE im slow i'll give you brainliest if you answer idkk what to do

Answers

Answer:Molecule:

a group of atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction.

Compound:

A compound is a material formed by chemically bonding two or more chemical elements. The type of bond keeping elements in a compound together may vary: covalent bonds and ionic bonds are two common types. The elements are always present in fixed ratios in any compound.

Element:

Chemical element, also called element, any substance that cannot be decomposed into simpler substances by ordinary chemical processes. Elements are the fundamental materials of which all matter is composed.

Mixture:

is a material made up of two or more different substances which are physically combined.

Chemical Formula:

A chemical formula identifies each constituent element by its chemical symbol and indicates the proportionate number of atoms of each element. I

Pure substance:

A substance that has a fixed chemical composition throughout is called a pure substance such as water, air, and nitrogen.

hope this help!

Answer:

Here are the definitions of all of them.

Explanation:

Molecule:

a group of atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction.

Compound:

A compound is a material formed by chemically bonding two or more chemical elements. The type of bond keeping elements in a compound together may vary: covalent bonds and ionic bonds are two common types. The elements are always present in fixed ratios in any compound.

Element:

Chemical element, also called element, any substance that cannot be decomposed into simpler substances by ordinary chemical processes. Elements are the fundamental materials of which all matter is composed.

Mixture:

is a material made up of two or more different substances which are physically combined.

Chemical Formula:

A chemical formula identifies each constituent element by its chemical symbol and indicates the proportionate number of atoms of each element. I

Pure substance:

A substance that has a fixed chemical composition throughout is called a pure substance such as water, air, and nitrogen.

the commands given in nucleus are throughout the cell by the

A.endoplamic reticulum
B.Flagella
C.mitochondria
D.golgi bodies
E.vacuole​

Answers

Answer:

A.endoplamic reticulum

Explanation:

The endoplamic reticulum  is an important organelle in protein synthesis. The nucleus contains DNA, which is the template for transcription of mRNA. mRNA acts as a message, which leaves the nucleus to become translated into proteins.

The endoplasmic reticulum is important in the synthesis, folding, and modification of proteins.  

Which lists three parts of sunlight that make up some of the visible spectrum?
O green, blue, indigo
O infrared, red, orange
ultraviolet infrared, electromagnetic
violet, ultraviolet A ultraviolet B
Brainly if correct Hurry

Answers

Answer:

Its A

Explanation:

Green, blue, indigo lists three parts of sunlight that make up some of the visible spectrum. Hence option with green, blue, indigo is correct.

What is Electromagnetic Spectrum ?

Electromagnetic spectrum is nothing but the range of wavelengths or frequencies on which electromagnetic radiation extend. it is whole distribution of electromagnetic waves according to frequency or wavelength. Electromagnetic wave is nothing but a photon which carries energy. Photon has frequency, wavelength as well as amplitude.

Electromagnetic spectrum is show in figure.

Range from 4000 angstrom to 7000 angstrom from violet to red respectively shows the visible light

Infrared light is nothing but the heat we feel from the sun. and ultraviolet light is blacked by ozone layer. we can calculate exact value of temperature of the sun rom Stephan's forth power law.

Green, blue, indigo, red and oranges are the colors from visible light, therefore they are part of visible light.

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the valency of nitrogen is 3 . Give reason​

Answers

Answer:

The nitrogen atom has 5 electrons in the outermost shell, so it can accept 3 electrons to fulfil the octet structure. Therefore the valency of nitrogen is 3.

For the equation 2 HCI + Zn ⇒ H₂ +ZnCI₂ suppose you had 2.00 g HCI and enough Zn.

a. What mass, in grams, would you have of Zn?

b. How many grams of H₂ would be produced?

Please show your work!!

Answers

Answer:

Zinc weighs 65.38 grams per mole, so we’ve got 0.994 moles of zinc (I’ll worry about sig figs at the end). HCl weighs 36.46 grams per mile, so we’ve got 1.78 moles of HCl. However, two moles of HCl react with one mole of zinc. So only 1.78/2 = 0.890 moles of Zinc are going to react.

One mole of zinc produces one mole of hydrogen, which weigh 2.02 grams per mole. So 0.890 moles * 2.02 grams/mole means 1.90 grams of hydrogen will be produced.

Since we have 2 sig figs in the weights given, the answer should have 2 sig figs, thus 1.9 grams.

This is just an example

Based on what you observed on the link above,
describe how ice in a teapot is turned into steam.
Liquid
lid


Answers

Answer: the particles in the water heats up and the hotter to gets the faster it moves. When there is no where for the heat to go it builds up and pushes its way out and turns to steam when it hits cool air

Explanation:

Some dog foods contains corn and wheat that provide the dog with carbohydrates. Which claim explains why carbohydrates are important to cell processes?

A) They are a source of energy.

B) They make amino acids.

C) They form cell membranes.

D) They help chemical processes happen.

(Science 7th grade)

Answers

Hello!

The answer is that they are a source of energy!

Hope this helps!

C is the correct answer.

how many seconds are in 1 year

Answers

31,536,000 that’s about right

How would you prepare 250.0ml of 0.5 M solution from 6 M stock solution of NaCl?

Answers

Answer:

I would place 0.5 M solution of the 6.0 stock solution to a 250 mL volumetric flask and then add 250 mL of water.

Explanation:

How can sediment be a bad thing??

Answers

Answer:

Sediment increases the cost of treating drinking water and can result in odor and taste problems. Sediment can clog fish gills, reducing resistence to disease, lowering growth rates, and affecting fish egg and larvae development.

Explanation:

Answer:

"Sediment increases the cost of treating drinking water and can result in odor and taste problems. Sediment can clog fish gills, reducing resistance to disease, lowering growth rates, and affecting fish egg and larvae development".

Explanation:


You were tasked to check if the liquid sample you have is a substance or a
mixture. Which among these tests is the BEST way to do so?l.color comparizon
lltaste comparizon
III. Boiling Test
IV. Melting Test
a.I, II, III and IV. b.l,II, and III only
c. I and Ill only
d. I, II, and IV only

Answers

Answer:

The correct answer is - option C.  I and Ill only.

Explanation:

One never tastes a unknown chemical in chemistry lab especialy a liquid that can be hazardous. Melting test is for solid as a solution is already a liquid state so melting test can not be perform on it.

The two test can be perform on given sample that are color comparison and boiling test to check if it is substance or a mixture. A misture is prepared from mixing different kind of compounds that can give different kind of color  while a particular substance give a uniform color always or remain colorless.

Boiling test can be helpful in distinguish a mixture from a substance as a particular sybstance always give a particular boiling point but mixture can be varry and depend of the coponents mixed together

Help!!!

A. A halogen
B. An alkaline earth metal
C. An alkali metal
D. A transition element

Answers

Answer:

B?

Explanation:

Which group is the most reactive?
*
Alkaline Earth Metals
Alkali metals
Noble Gases
Lanthanides

Answers

Answer:

alkali metals- Group 1

Explanation:

they have less valence electrons and therefore are more reactive

Calculate the volume of a 0.750 M solution containing 67.0 g of KNO3

(gives you 20 points!)

Answers

Answer:

Volume of solution is 0.88 L.

Explanation:

Given data:

Molarity of solution = 0.750 M

Mass of KNO₃ = 67.0 g

Volume of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles.

Number of moles = mass/molar mass

Number of moles = 67.0 g/ 101.1 g/mol

Number of moles = 0.66 mol

Now we will put the values in molarity formula.

0.750 M = 0.66 mol / L of solution

L of solution  = 0.66 mol / 0.750 M

L of solution  = 0.88 L

Volume of solution is 0.88 L.

When warm air from a large body of water

Answers

Answer:

On a warm day, water absorbs from its warmer environment, lowering the air tempurature. On a cool night, heat is transferred from the water to its cooler environment, raising the air tempura

Explanation:

(A) Hemoglobin is 50% saturated (P50) at 20 torr, which is approximately equal to the partial pressure of O2 in muscle. The partial pressure of O2 in the lungs is 100 torr. If the Hill coefficient nh = 3, calculate how efficient hemoglobin is at O2 delivery. Express your answer as the difference between factional O2 binding in the lungs and fractional O2 binding in muscle (qlungs – qmuscle). (B) How would the efficiency of O2 delivery change if hemoglobin were not cooperative (i.e. if nh =1)?

Answers

Answer:

Explanation:

Given that:

P₅₀ = 20 torr in muscle

The partial pressure of O2 in lungs Po₂ = 100 torr

The hill coefficient [tex]n_h[/tex] = 3

According to the Hill coefficient;

[tex]\dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{PO_2}{P_{50}})^n[/tex]

here;

[tex]\Upsilon[/tex] = fraction of haemoglobin monomers

[tex]\dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{100}{20})^3[/tex]

[tex]\dfrac{\Upsilon}{1-\Upsilon}[/tex] = 125 θ lungs

However for θ muscle :

[tex](\dfrac{PO_2}{P_{50}})^n=( \dfrac{20}{20})^3[/tex]

= 125 (θ lungs) - 1 (θ muscle)

= 124

B.

if nh =1

[tex]\mathtt {\theta \ lungs} = \dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{100}{20})^1[/tex]

[tex]\mathtt {\theta \ lungs} =5[/tex]

[tex]\mathtt {\theta \ muscle} = \dfrac{20}{20}^1[/tex]

(θ muscle) = 1

(θ lungs) - (θ muscle) = 5 - 1

(θ lungs) - (θ muscle) = 4

A) The efficiency of hemoglobin at O₂ delivery = 124

B) Efficiency of O₂ delivery will change by : 4  

Given data:

Partial pressure of O₂ in lungs ( PO₂ )  = 100 torr

Partial pressure of O₂ in muscle  = ( P₅₀ ) = 20 torr

Hill coefficient nh = 3

r = fraction of hemoglobin monomers

A) Determine the efficiency of hemoglobin at O₂ delivery

Given that Hill coefficient = [tex]\frac{r}{1-r} = (\frac{PO_{2} }{P_{50} } )^{n}[/tex]  

                                          = [tex]\frac{r}{1-r} = (\frac{100}{20})^{3}[/tex]  = 125 ∅ Lungs

For Muscle :

[tex](\frac{20}{20} )^{3}[/tex] =  1 ∅ muscle

Therefore the efficiency of hemoglobin at 0₂ delivery

= ( ∅ lungs - ∅ muscle )

=  ( 125 - 1 )  = 124

B )  Determine the change in efficiency of O2 delivery

when hill coefficient ( nh ) = 1

for lungs :

[tex]\frac{r}{1-r} = (\frac{100}{20})^{1}[/tex]  = 5

for muscle :

[tex](\frac{20}{20} )^{1}[/tex]   = 1

Therefore change on efficiency =  ( 5 - 1 ) = 4

Hence we can conclude that The efficiency of hemoglobin at O₂ delivery = 124 and Efficiency of O₂ delivery will change by  4  

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