Answer: 4/3
Step-by-step explanation:
i keel asking for the dang answer why wont anyone tell me it a store sells pencils pens and markers that sells two times as many markers as pencils and three times as many pens as pencils is the store sells a total of 1950 pencils and pens and markers in a week how many of each were sold
Answer:
Pencils = 325 ; Pens = 975 ; Markers = 650
Step-by-step explanation:
Let :
Number of Pencils = x
Number of pens = y
Number of markers = z
2 times as many markers as pencils
z = 2x
3 times as many pens as pencils
y = 3x
x + y + z = 1950
Write z and y in terms of x in the equation :
x + 3x + 2x = 1950
6x = 1950
Divide both sides by 6
6x / 6 = 1950 / 6
x = 325
Number of pencils = 325
Pens = 3 * 325 = 975
Markers = 2 * 325 = 650
Pencils = 325 ; Pens = 975 ; Markers = 650
Resistors for electronic circuits are manufactured on a high-speed automated machine. The machine is set up to produce a large run of resistors of 1,000 ohms each. Use Exhibit 10.13. To set up the machine and to create a control chart to be used throughout the run, 15 samples were taken with four resistors in each sample. The complete list of samples and their measured values are as follows: Use three-sigma control limits. SAMPLE NUMBER READINGS (IN OHMS) 1 1027 994 977 994 2 975 1013 999 1017 3 988 1016 974 997 4 998 1024 1006 1010 5 990 1012 990 1000 6 1016 998 1001 1030 7 1000 983 979 971 8 973 982 975 1030 9 992 1028 991 998 10 997 1026 972 1021 11 990 1021 1028 992 12 1021 998 996 970 13 1027 993 996 996 14 1022 981 1014 983 15 977 993 986 983 a. Calculate the mean and range for the above samples.
Answer:
See explanation
Step-by-step explanation:
Given
See attachment for proper presentation of question
Required
Mean and Range
To do this, we simply calculate the mean and the range of each row.
[tex]\bar x = \frac{\sum x}{n}[/tex] ---- mean
Where:
[tex]n = 4[/tex] ---- number of rows
[tex]R = Highest - Lowest[/tex] --- range
So, we have:
Sample 1
[tex]\bar x_1 = \frac{1027+ 994 +977 +994 }{4}[/tex]
[tex]\bar x_1 = 998[/tex]
[tex]R_1 = 1027- 994[/tex]
[tex]R_1 = 33[/tex]
Sample 2
[tex]\bar x_2 = \frac{975 +1013 +999 +1017}{4}[/tex]
[tex]\bar x_2 = 1001[/tex]
[tex]R_2 = 1017 - 975[/tex]
[tex]R_2 = 42[/tex]
Sample 3
[tex]\bar x_3 = \frac{988 +1016 +974 +997}{4}[/tex]
[tex]\bar x_3 = 993.75[/tex]
[tex]R_3 = 1016-974[/tex]
[tex]R_3 = 42[/tex]
Sample 4
[tex]\bar x_4 = \frac{998 +1024 +1006 +1010}{4}[/tex]
[tex]\bar x_4 = 1009.5[/tex]
[tex]R_4 = 1024 -998[/tex]
[tex]R_4 = 26[/tex]
Sample 5
[tex]\bar x_5 = \frac{990 +1012 +990 +1000}{4}[/tex]
[tex]\bar x_5 = 998[/tex]
[tex]R_5 = 1012 -990[/tex]
[tex]R_5 = 22[/tex]
Sample 6
[tex]\bar x_6= \frac{1016 + 998 +1001 +1030}{4}[/tex]
[tex]\bar x_6= 1011.25[/tex]
[tex]R_6= 1030-998[/tex]
[tex]R_6= 32[/tex]
Sample 7
[tex]\bar x_7 = \frac{1000 +983 +979 +971}{4}[/tex]
[tex]\bar x_7 = 983.25[/tex]
[tex]R_7 = 1000-971[/tex]
[tex]R_7 = 29[/tex]
Sample 8
[tex]\bar x_8 = \frac{973 +982 +975 +1030}{4}[/tex]
[tex]\bar x_8 = 990[/tex]
[tex]R_8 = 1030-973[/tex]
[tex]R_8 = 57[/tex]
Sample 9
[tex]\bar x_9 = \frac{992 +1028 +991 +998}{4}[/tex]
[tex]\bar x_9 = 1002.25[/tex]
[tex]R_9 = 1028 -991[/tex]
[tex]R_9 = 37[/tex]
Sample 10
[tex]\bar x_{10} = \frac{997 +1026 +972 +1021}{4}[/tex]
[tex]\bar x_{10} = 1004[/tex]
[tex]R_{10} = 1026 -972[/tex]
[tex]R_{10} = 54[/tex]
Sample 11
[tex]\bar x_{11} = \frac{990 +1021 +1028 +992}{4}[/tex]
[tex]\bar x_{11} = 1007.75[/tex]
[tex]R_{11} = 1028 -990[/tex]
[tex]R_{11} = 38[/tex]
Sample 12
[tex]\bar x_{12} = \frac{1021 +998 +996 +970}{4}[/tex]
[tex]\bar x_{12} = 996.25[/tex]
[tex]R_{12} = 1021 -970[/tex]
[tex]R_{12} = 51[/tex]
Sample 13
[tex]\bar x_{13} = \frac{1027 +993 +996 +996}{4}[/tex]
[tex]\bar x_{13} = 1003[/tex]
[tex]R_{13} =1027 -993[/tex]
[tex]R_{13} =34[/tex]
Sample 14
[tex]\bar x_{14} = \frac{1022 +981 +1014 +983}{4}[/tex]
[tex]\bar x_{14} = 1000[/tex]
[tex]R_{14} = 1022 -981[/tex]
[tex]R_{14} = 41[/tex]
Sample 15
[tex]\bar x_{15} = \frac{977 +993 +986 +983}{4}[/tex]
[tex]\bar x_{15} = 984.75[/tex]
[tex]R_{15} = 993-977[/tex]
[tex]R_{15} = 16[/tex]
Q: EXPRESS IT IN THE FORM OF LINEAR EQUATION IN ONE VARIABLE:
•The ordinate of a point is thrice its abscissa.
Answer:
y = 3x
Step-by-step explanation:
abscissa is the x coordinate
ordinate is the y coordinate
y = 3x
write your answer in simplest radical form
Answer:
c = 4√2
Step-by-step explanation:
From the question given above, the following data were obtained:
Angle θ = 30
Opposite = 2√2
Hypothenus = c =?
We can obtain the value of c by using the sine ratio as illustrated below:
Sine θ = Opposite / Hypothenus
Sine 30 = 2√2 / c
½ = 2√2 / c
Cross multiply
c = 2 × 2√2
c = 4√2
Therefore, the value of c is 4√2.
The number formed by adding 1 to the greatest 8 – digit number is?
Answer:
the answer would be 100,000,000
Greatest 8 Digit Number: 99,999,999
Adding 1 = 99999999+1
= 100,000,000
Must click thanks and mark brainliest
What is the value of x?
X + y = 10;
Z + z = 6;
Z + y = 5;
A) 9
B) 8
C) 7
D) 6
E) 1
Answer:
B
Step-by-step explanation:
z+z=6, z=3. z+y=5, y=2, x+y=10, x=8
A 500-kg concrete block 95 cm longcm wide and cm high. It can exert three different pressures on a horizontal surface depending on which faceit rests on the highest pressure is
Pressure is force per unit area. If the block is sitting at rest on the surface, it applies a pressure of mg/A, where mg is the block's weight and A is the area of the face that makes contact with the surface.
The smaller the value of A, the larger the pressure. So the highest pressure the block can exert is achieved when it's resting on the face with the smallest dimensions.
If the block is a cube with side length 95 cm, then the pressure exerted by each face is the same.
The initial population of the town was estimated to be 12,500 in 2005. The population has increased by about 5.4% per year since 2005.
Formulate the equation that gives the population, A(x) , of the town x years since 2005. If necessary, round your answer to the nearest thousandth.
A(x)=__(_)^x
Answer:
[tex]A(x) = 12500(1.054)^x[/tex]
Step-by-step explanation:
Exponential equation for population growth:
Considering a constant growth rate, the population, in x years after 2005, is given by:
[tex]A(x) = A(0)(1 + r)^x[/tex]
In which A(0) is the population in 2005 and r is the growth rate, as a decimal.
The initial population of the town was estimated to be 12,500 in 2005.
This means that [tex]A(0) = 12500[/tex]
The population has increased by about 5.4% per year since 2005.
This means that [tex]r = 0.054[/tex]
So
[tex]A(x) = A(0)(1 + r)^x[/tex]
[tex]A(x) = 12500(1 + 0.054)^x[/tex]
[tex]A(x) = 12500(1.054)^x[/tex]
Please help me to find this problem
9514 1404 393
Answer:
3. 42.21 in
4. 4.38 cm
Step-by-step explanation:
The mnemonic SOH CAH TOA is intended to remind you of the relationships between an angle in a right triangle and the basic trig functions. The triples of letters stand for ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
Tan = Opposite/Adjacent
where the terms "opposite" and "adjacent" refer to sides of the triangle that are opposite the angle of interest or adjacent to it, respectively.
In these problems, the measure of the hypotenuse is shown, and the problem requests the measure of the side opposite the given angle. The sine function is relevant.
__
3. sin(79°) = GE/GB = GE/(43 in)
GE = (43 in)sin(79°) ≈ (43 in)(0.981627) ≈ 42.21 in
__
4. sin(26°) = BC/BA = BC/(10 cm)
BC = (10 cm)sin(26°) ≈ (10 cm)(0.438371) ≈ 4.38 cm
Tìm đạo hàm riêng cấp 1 của hàm số:
f(x,y) = e^(x²+y²) + 3x . e^xy
Answer:
fx = 2xe^(x^2+y^2) + 3e^xy + 3xye^xy
fy = 2ye^(x^2+y^2) + 3x^2.e^xy
Find the equation of a line that is perpendicular to x+y=8 and passes through the point (8, 10).
Answer:
Y = -x + 2
Step-by-step explanation:
y = -x + 8
y = 1x + b
10 = 8 + b
b = 2
Answer:
y-y1=m(x-x1)
y-10=8(x-8)
y-10=8x-64
y-10+64-8x
y+54-8x
y-8x+54
Let θ be an angle in quadrant IV such that sinθ = -2/5 .
Find the exact values of secθ and tanθ.
If θ lies in the fourth quadrant, then sin(θ) < 0 and cos(θ) > 0. So we have from the Pythagorean identity,
sin²(θ) + cos²(θ) = 1 ==> cos(θ) = +√(1 - sin²(θ)) = √21/5
Then
sec(θ) = 1/cos(θ) = 5/√21
and
tan(θ) = sin(θ)/cos(θ) = (-2/5)/(√21/5) = -2/√21
Find the length of the segment indicated. Round your answer to the nearest tenth if necessary.
Answer:
x=5
Step-by-step explanation:
im so bad at explaining things but i hope this helped
i need help on this PLS
Answer:
25 miles (The pattern is m = 25g where m is miles and g is gallons.)
A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A. We are interested in determining whether or not the proportion of the population in favor of Candidate A is significantly more than 40%. The test statistic is a.1.44. b.1.25. c..95. d..80.
Answer:
a. 1.44
Step-by-step explanation:
We are interested in determining whether or not the proportion of the population in favor of Candidate A is significantly more than 40%.
At the null hypothesis, it is tested if the proportion is of at most 40%, that is:
[tex]H_0: p \leq 0.4[/tex]
At the alternative hypothesis, it is tested if the proportion is of more than 40%, that is:
[tex]H_1: p > 0.4[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
0.4 is tested at the null hypothesis:
This means that [tex]p = 0.4, \sigma = \sqrt{0.4*0.6}[/tex]
A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A.
This means that:
[tex]n = 200, X = \frac{90}{200} = 0.45[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{0.45 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{200}}}[/tex]
[tex]z = 1.44[/tex]
Thus the correct answer is given by option a.
What is the solution of the equation x2 -14x + 67 = 0?
A. X= 7+3in12
B.X = 7+31V-2
C.X= 7+ 2/8
D.X = 7+ 217
[tex]\sf\huge\underline\color{pink}{༄Answer:}[/tex]
What is the solution of the equation x^2 - 14x + 67 = 0?
[tex]\tt{First \: option. \: x = 7 \underline{+}3i\sqrt{2}}[/tex][tex]\color{pink}{==========================}[/tex]
#CarryOnLearning
[tex]\sf\color{pink}{༄⁂✰Bae \: Yoonah}[/tex]
If a cube has an edge of length e, then the lateral surface area is:
Answer:
The total lateral surface of this cube is 4*e^2
Step-by-step explanation:
A cube is a figure with all the sides of the same length, so each face of a cube is a square.
Remember that the area of a square of sidelength L is:
A = L^2
Now, when we want to find the lateral surface of a figure, we ignore the bases of the figure.
So, if a cube has 6 faces, if we ignore the two bases, we are left with 4 square faces.
And if the edge length is e, then each one of these four faces has an area:
A = e^2
So the total lateral surface is 4 times that:
S = 4*e^2
The total lateral surface of this cube is 4*e^2
Answer:
4e2
Step-by-step explanation:
I got it correct on founders edtell
Al gave correct answers to 22 of the 25 questions on the driving test. What percent of the questions did he get correct?
Let S be a set of linearly dependent vectors in Rn. Select the best statement. A. The set S could, but does not have to, span Rn. B. The set S spans Rn, as long as no vector in S is a scalar multiple of another vector in the set. C. The set S cannot span Rn. D. The set S must span Rn. E. The set S does not span Rn if some vector in S is a scalar multiple of another vector in the set. F. The set S spans Rn, as long as it does not include the zero vector. G. none of the above
Answer:
The set S could, but does not have to, span Rn ( A )
Step-by-step explanation:
Assume S is a set of linearly dependent vectors in Rn
The best statement from the options is ; The set S could, but does not have to, span Rn
This is because S could span Rn ( as stated in option c ) but will not necessary span Rn ( as seen in option D )
A semi-circle sits on top of a rectangle to form the figure below. Find its area and perimeter. Use 3.14 for a.
2 in.
4 in.
O A = 33.12 square inches, P = 20.56 inches
O A 14.28 square inches, P20.56 inches
A = 33.12 square inches, P = 14.28 inches
O A 14.28 square inches, P = 14.28 inches
9514 1404 393
Answer:
(d) A = 14.28 in², P = 14.28 in
Step-by-step explanation:
The figure is wholly contained within a 4" square, which has an area of (4 in)² = 16 in², and a perimeter of 4(4 in) = 16 in. Since the figure is smaller in area and has a shorter perimeter (the top corners are rounded, not square), both answer values must be less than 16.
The only reasonable choice is the last choice: 14.28 in², 14.28 in.
__
If you want to figure this out in detail, you have the area of a rectangle that is 2 in by 4 in, and the area of a semicircle of radius 2 in. The total area is ...
A = LW +1/2πr²
A = (2 in)(4 in) + 1/2(3.14)(2 in)² = 8 in² +6.28 in²
A = 14.28 in²
__
The perimeter is half that of a 4" square, plus half that of a 4" circle.
P = 1/2(4(4 in) +π(4 in)) = (2 in)(4 +π) = 2(7.14) in
P = 14.28 in
Quy tắc suy luận nào là cơ sở của suy diễn sau: "Biết rằng: 2 đường thẳng d và d' song song hoặc cắt nhau. Ta đã có d không song song với d'. Vậy d cắt d'
Select one:
a. Luật loại trừ
b. Luật rút gọn
c. Luật phản chứng
d. Luật tách rời
Answer: a
Step-by-step explanation:
8 thousand+7tens=6thiusand+. tens
Answer:
207 tens
Step-by-step explanation:
If you mean
8,000 + 70 = 6000 + X tens
then it should be 207 tens
1. Carlos wants to deposit $900 into savings accounts at three different
banks: Bank of Chance, Merchant Bank, and Utopian Financing. He will
deposit two times as much into Merchant Bank as Bank of Chance
because they offer a higher interest rate. He also expects the Utopian
Financing deposit to be only 20% of the total of the other two deposits.
How much will Carlos deposit into the Utopian Financing savings account
(4 points)
O $180
$250
$500
$150
Answer:
$150
Step-by-step explanation:
0.2 X 750 = 150
hope this helps
We are given a weighted coin (with one side heads, one side tails), and we want to estimate the unknown probability pp that it will land heads. We flip the coin 1000 times and it happens to land heads 406 times. Give answers in decimal form, rounded to four decimal places (or more). We estimate the chance this coin will land on heads to
Answer:
0.4060
Step-by-step explanation:
To calculate the sample proportion, phat, we take the ratio of the number of preferred outcome to the total number of trials ;
Phat = number of times coin lands on head (preferred outcome), x / total number of trials (total coin flips), n
x = 406
n = 1000
Phat = x / n = 406/ 1000 = 0.4060
The estimate of the chance that this coin will land on heads is 0.406
Probability is the likelihood or chance that an event will occur.Probability = Expected outcome/Total outcomeIf a coin is flipped 1000 times, the total outcomes will 1000
If it landed on the head 406 times, the expected outcome will be 406.
Pr(the coin lands on the head) = 406/1000
Pr(the coin lands on the head) = 0.406
Hence the estimate of the chance that this coin will land on heads is 0.406
Learn more on probability here: https://brainly.com/question/14192140
For an avid bird watcher, the probability of spotting a California Condor while birdwatching in the Grand Canyon area is 0.3. The probability of being able to take a clear picture of the bird suppose one is able to spot it is 0.8. What is the probability that the bird watcher is able to take a clear picture of a California Condor
Answer:
the probability of taking a clear picture of a California candor is .24
Bod and coa are _____ angles
Answer:
opposite angles
Step-by-step explanation:
They are formed in the intersection of lines AD and BD.
Answer:
opposite angles
Step-by-step explanation:
they are formed in the intersection of lines AD and BD. two figures are called similar if they have same shape however have different size.
72
60
48
36
Number of Computers
The graph shows a proportional relationship between
the number of computers produced at a factory per
day in three days, 36 computers are produced, 48
computers are produced in 4 days, and 60 computers
are produced in 5 days.
Find the unit rate of computers per day using the
graph.
Unit rate
computers per day
I
24
12
3 4 5 6 7 8 9 10 11 12
Number of Days
Intro
Done
Graph is attached below ;
Answer:
Unit rate = 12 computers per day
Step-by-step explanation:
To obtain the unit rate of computers sold per day using the graph, we need to obtain the slope of the graph, which is the change in y per change in x
That is ; the gradient ;
Slope = change in y / change in x
Slope = (y2 - y1) / (x2 - x1)
y2 = 60 ; y1 = 36 ; x2 = 5 ; x1 = 3
Slope = (60 - 36) / (5 - 3) = 24 / 2 = 12
Slope = 12
Unit rate = 12 computers per day
need help asap pls! :)
Answer:
6:21
Step-by-step explanation:
We want to find the ratio of squares to shapes
So simply count the squares
There are 6 squares
And then find the total number of shapes
There are a total of 21 shapes
So for every 6 squares there are 21 total shapes
In other words the ratio of squares to shapes is 6:21
Answer:
6:21Step-by-step explanation:
Given,
Number of squares = 6
Total no. of shapes = 21
Therefore,
Unsimplified ratio of squares to total shapes
= 6:21 (Ans)
solve similar triangles (advanced)
solve for x
Answer:
x = 27/8
Step-by-step explanation:
We can write a ratio to solve
x 3
------- = ----------
x+9 11
Using cross products
x*11 = 3(x+9)
11x = 3x+27
Subtract 3x from each side
8x = 27
8x/8 = 27/8
x = 27/8
The The Laplace Transform of a function , which is defined for all , is denoted by and is defined by the improper integral , as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of as a fixed constant) 1. Find (hint: remember integration by parts)
Answer:
a. L{t} = 1/s² b. L{1} = 1/s
Step-by-step explanation:
Here is the complete question
The The Laplace Transform of a function ft), which is defined for all t2 0, is denoted by Lf(t)) and is defined by the improper integral Lf))s)J" e-st . f(C)dt, as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of s as a fixed constant) 1. Find Lft) (hint: remember integration by parts) A. None of these. B. O C. D. 1 E. F. -s2 2. Find L(1) A. 1 B. None of these. C. 1 D.-s E. 0
Solution
a. L{t}
L{t} = ∫₀⁰⁰[tex]e^{-st}t[/tex]
Integrating by parts ∫udv/dt = uv - ∫vdu/dt where u = t and dv/dt = [tex]e^{-st}[/tex] and v = [tex]\frac{e^{-st}}{-s}[/tex] and du/dt = dt/dt = 1
So, ∫₀⁰⁰udv/dt = uv - ∫₀⁰⁰vdu/dt w
So, ∫₀⁰⁰[tex]e^{-st}t[/tex] = [[tex]\frac{te^{-st}}{-s}[/tex]]₀⁰⁰ - ∫₀⁰⁰ [tex]\frac{e^{-st}}{-s}[/tex]
∫₀⁰⁰[tex]e^{-st}t[/tex] = [[tex]\frac{te^{-st}}{-s}[/tex]]₀⁰⁰ - ∫₀⁰⁰ [tex]\frac{e^{-st}}{-s}[/tex]
= -1/s(∞exp(-∞s) - 0 × exp(-0s)) + [tex]\frac{1}{s}[/tex] [[tex]\frac{e^{-st} }{-s}[/tex]]₀⁰⁰
= -1/s[(∞exp(-∞) - 0 × exp(0)] - 1/s²[exp(-∞s) - exp(-0s)]
= -1/s[(∞ × 0 - 0 × 1] - 1/s²[exp(-∞) - exp(-0)]
= -1/s[(0 - 0] - 1/s²[0 - 1]
= -1/s[(0] - 1/s²[- 1]
= 0 + 1/s²
= 1/s²
L{t} = 1/s²
b. L{1}
L{1} = ∫₀⁰⁰[tex]e^{-st}1[/tex]
= [[tex]\frac{e^{-st} }{-s}[/tex]]₀⁰⁰
= -1/s[exp(-∞s) - exp(-0s)]
= -1/s[exp(-∞) - exp(-0)]
= -1/s[0 - 1]
= -1/s(-1)
= 1/s
L{1} = 1/s
