-2x -3 =5 what dose x = to

Answer:

650,000,000

Step-by-step explanation:

6.5x10^8

Answer:

1

Step-by-step explanation:

Answer:

g) 2 h) 4

Step-by-step explanation:

g) The time t when the instantaneous velocity of the positron is zero is;

t = 2

h) The location of the positron at the time of t = 2 is;

p = 4.

g) We are told that the function that models the position of the sub atomic particles is;

p(t) = t²/(t - 1)

Instantaneous velocity is simply the derivative of the distance with respect to time.

Thus, Instantaneous velocity is gotten by using online differentiation calculator to get; dp/dt = [2t/(t - 1)] - [t²/(t - 1)²]

When Instantaneous velocity is zero, we have;

[2t/(t - 1)] - [t²/(t - 1)²] = 0

Rearranging to get;

[2t/(t - 1)] = [t²/(t - 1)²]

Cross multiply to get;

2t(t - 1)² = t²(t - 1)

divide both sides by t to get;

2(t - 1)² = t(t - 1)

Expand the bracket to get;

2(t² - 2t + 1) = t² - t

2t² - 4t + 2 = t² - t

Rearrange to get;

t² - 3t + 2 = 0

Using online quadratic equation solver gives;

t = 1 or 2

We are told that t > 1

Thus, we will adopt t = 2

h) At t = 2 seconds gotten in g above, the positron is located at;

p(2) = 2²/(2 - 1)

p(2) = 4

Read more at; https://brainly.com/question/2020753

Answer:

1+4+7

2+4+6

3+4+5

Step-by-step explanation:

Answer:

6+4+2=12     5+4+3 =12

Step-by-step explanation:

Answer:

ggggmd

hsmhdmvx.hffyfylltet

Answer:

It would be 58 degrees

Step-by-step explanation:

Hope it helps :)

Answer:

[tex]y = \frac{2}{3} + 7[/tex]

Answer:

a. Sketch is given in the attachment

b. [tex]V_{p}[/tex] = (0,-525)

c. [tex]V_{w}[/tex] = ([tex]\sqrt{2}[/tex],[tex]\sqrt{2}[/tex])  

d. [tex]V_{g}[/tex] = (60[tex]\sqrt{2}[/tex], 60[tex]\sqrt{2}[/tex]  - 525)

e. Actual Speed = |[tex]V_{g}[/tex]| = 448.3 MPH

Direction = Ф = - 79.1°

Direction = Ф = 280.9° with respect to x - axis.

Step-by-step explanation:

a. Sketch the scenario on the x-y axis.

Where,

Velocity of the plane relative to air = [tex]V_{p}[/tex]

Velocity of the jet stream = [tex]V_{w}[/tex]

Velocity of the plane relative to ground = [tex]V_{g}[/tex]

Solution:

Note: Solution is given in the attachment. Please refer to the attachment for the sketch.

b. Express the velocity of the plane relative to the air as a vector.

Solution:

[tex]V_{p}[/tex] = |[tex]V_{p}[/tex]| cosФi + |[tex]V_{p}[/tex]| sinФj

where,

|[tex]V_{p}[/tex]| = magnitude of the vector.

|[tex]V_{p}[/tex]| =  525 MPH

Ф = 270° w.r.t to x - axis. (See the sketch in the attachment)

[tex]V_{p}[/tex] = |[tex]V_{p}[/tex]| cosФi + |[tex]V_{p}[/tex]| sinФj

Plug in the values into this equation to express it in the vector form as required.

[tex]V_{p}[/tex] = (525) cos270i + (525) sin270j

As, Cos270 = 0

and

Sin270 = -1

So,

[tex]V_{p}[/tex] = (525) (0)i + (525) (-1)j

[tex]V_{p}[/tex] = 0i -525j    

[tex]V_{p}[/tex] = (0,-525)  

c. Express the velocity of the jet stream as a vector.

Solution:

Velocity of the jet stream as a vector.

[tex]V_{w}[/tex] = |[tex]V_{w}[/tex]| cosФi + |[tex]V_{w}[/tex]| sinФj

where,

|[tex]V_{w}[/tex]| = magnitude of the vector.

|[tex]V_{p}[/tex]| =  120 MPH

Ф = 45°  (See the sketch in the attachment)

[tex]V_{w}[/tex] = |[tex]V_{w}[/tex]| cosФi + |[tex]V_{w}[/tex]| sinФj

Plug in the values into this equation to express it in the vector form as required.

[tex]V_{w}[/tex] = (120) cos45i + (120) sin45j

As, Cos45 = [tex]\frac{1}{\sqrt{2} }[/tex]

and

Sin45 =  [tex]\frac{1}{\sqrt{2} }[/tex]

So,

[tex]V_{w}[/tex] = (120) ([tex]\frac{1}{\sqrt{2} }[/tex])i + (120) ([tex]\frac{1}{\sqrt{2} }[/tex])j

[tex]V_{w}[/tex] = 60[tex]\sqrt{2}[/tex]i +60[tex]\sqrt{2}[/tex]j    

[tex]V_{w}[/tex] = ([tex]\sqrt{2}[/tex],[tex]\sqrt{2}[/tex])  

d. Find the velocity of the plane relative to the ground.

Solution:

Velocity of the plane relative to the ground = Sum of velocity of plane relative to the air and velocity of the jet stream

[tex]V_{g}[/tex] = [tex]V_{p}[/tex] + [tex]V_{w}[/tex]

[tex]V_{g}[/tex] = 0i -525j    +  60[tex]\sqrt{2}[/tex]i +60[tex]\sqrt{2}[/tex]j    

[tex]V_{g}[/tex] = 60[tex]\sqrt{2}[/tex]i + 60[tex]\sqrt{2}[/tex]  - 525j

[tex]V_{g}[/tex] = (60[tex]\sqrt{2}[/tex], 60[tex]\sqrt{2}[/tex]  - 525)

e. Find the actual speed and direction of the plane relative to the ground. Round to the  tenths.

Solution:

Actual Speed = |[tex]V_{g}[/tex]|  = magnitude of the velocity of the plane relative to the ground.

Actual Speed = |[tex]V_{g}[/tex]| = [tex]\sqrt{(60\sqrt{2}) ^{2} + (60\sqrt{2}-525) ^{2} }[/tex]

Actual Speed = |[tex]V_{g}[/tex]| = 448.3 MPH

Direction = Ф = [tex]tan^{-1}[/tex] ([tex]\frac{60\sqrt{2}-525 }{60\sqrt{2} }[/tex])

Direction = Ф = - 79.1°

To find out the direction with respect to x - axis.

Direction = Ф = 360 - 79.1

Direction = Ф = 280.9°

Answer:

12-n

Step-by-step explanation:

im confused but sure

3/4 of 80 = 60.

First off let's start with 1/4 of 80.

80/4 = 20.

But the question asks for 3/4 and that’s three times more than 1/4 so you multiply 3 to 20.

20*3 = 60.

So your answer is 60.

Answer:

9/16

Step-by-step explanation:

;)

Answer:

-0.5625

Step-by-step explanation:

-0.75 x 0.75 = -0.5625

Answer:

x=95

Step-by-step explanation:

They are vertical angles

Answer:

39 in³

Step-by-step explanation:

Pyramid volume: v = 1/3Bh    b=13 h=9

volume; 1/3 * 13 * 9 = 39

Answer:

4

Step-by-step explanation:

4² = 16

Answer:

y-3 = -4 (x-1)

Step-by-step explanation:

y= -4x - 5

In slope-intercept form, they give us the slope, -4, and the y-intercept, -5 (we don't need for point-slope form).

Use the point (1,3) and substitute it into the equation.

Point-slope form: y-y1 = m(x-x1)

y-3 = -4 (x-1)

Answer:

k = 11

Step-by-step explanation:

Expand brackets

2k - 10 = 12

add 10 on both sides

2k = 22

divide both sides by 2

k = 11

Answer:

Neither, why... for it to be direct or inverse variation, the model has to fit either y=k/x or y=kx, it may not have a y-intercept at all if it is inverse variation and it must have a y-intercept of 0 for it to be direct variation.

Step-by-step explanation:

The statement y=2 is quite specific. Because k is positive, y increases as x increases. So as x increases by 1, y increases by 1.5. Inverse Variation: Because k is positive, y decreases as x increases.  yx is a constant number -8. The constant of variation, k , is 23 . Inverse Variation

An inverse variation can be represented by the equation xy=k or y=kx .

That is, y varies inversely as x if there is some nonzero constant k such that, xy=k or y=kx where x≠0,y≠0 .

Suppose y varies inversely as x such that xy=3 or y=3x . That graph of this equation shown.

Answer:

The Population is 865000

Step-by-step explanation:

0.7 Million is equal to 700,000

700,000 + 165,000=865000

Answer:

water has be taken to separate and has been take the Kyon bag and tricks to win their water to bag and separate the tube and water the

Answer:

I am not the person to answer this question but the answer is B or74/3

10 Miles Because 25-15=10

Answer:

the answer would be about 28.60 km

Answer:

28 KM

Step-by-step explanation:

As an estimation we are told 5 miles is 8 km

mathematically , 5 miles = 8 KM

So , therefore 1 miles = 8/5 KM

now just , multiply 17.8 with 8/5

Answer:

$1.28 per liter

Step-by-step explanation:

750ml/1 L = .75

.96/.75 = 1.28

Answer:           x(2x=1)(x+1)-3(2x+1)(x+1)

Step-by-step explanation:

Answer: $54 / 3 = $27 for each girl

Step-by-step explanation:

Answer:

33 : 15 : 6

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

good luck