22% of the customers visiting the suit department of a certain store will purchase a suit, 30% will purchase a shirt and 28% will purchase a tie. 11% of customers purchase a shirt and a suit, 14% both a suit and a tie and 10% buy a shirt and a tie. Only 6% of customers buy all three items. Let A be the event that the customer purchases a suit, B the event that the customer purchases a shirt and C the event that the customer purchases a tie. If there are 1000 customers in the store one week, how many will purchase exactly one of these items

Answers

Answer 1

Answer:

If there are 1000 customers in the store one week, how many will purchase exactly one of these items

1000 CUSTOMERS*28%=280

Step-by-step explanation:

A The event that a persons buys a suit  

B The event that a person buys a shirt  

C The event that a person buys a tie  

 

P(A)=  22%

P(B)=  30%

P(C)=  28%

P(AB)= 11%

P(AC)= 14%

P(BC)= 10%

P(ABC)= 6%

A u B u C Is the event that any item is bougth

AC u AC u BC Is the event that any two events occured

So the wanted probability is

P[(A u B u C )(AB u AC u BC)^c

P[(A u B u C )=P(AB)+ P(BC)+P(BC)

P[(A u B u C ) =0.22+0.30+0.28-0.11-0.14.-0.10+0.06

                      =0,51

0,51=+0,23+P[(A u B u C )(AB u AC u BC)^c

        =0,28

1000 CUSTOMERS*28%=280


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Answer:

Yes

Step-by-step explanation:

You can do this

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Answer:

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Step-by-step explanation:

Heres your answer.

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Answers

9514 1404 393

Answer:

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Step-by-step explanation:

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__

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Answer:

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got 100% percent on the quiz

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Tuesday, January 5th
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