Answer:
40.0 c
Explanation:
Answer:
29.09 degree Celsius is final temperature
If two metals had the same specific heat, how can we distinguish them in two ways?
Answer:
Specific heat is an intensive property (like density, color, etc.) that does not depend on the amount of a substance present. This allows substances to be identified using their specific heat. Imagine an unknown metal of known mass is heated to a known temperature.
Explanation:
true or false:Earth's atmosphere is composed of about 78 percent nitrogen, 21 percent oxygen, 0.9 percent argon, and 0.1 percent other gases
Answer:
True
Explanation:
This is true.
Earth's atmosphere is composed of about 78 percent nitrogen, 21 percent oxygen, 0.9 percent argon, and 0.1 percent other gases is a true statement.
What are the main components of the atmosphere?The main components of the Earth's atmosphere are nitrogen (78%) and oxygen (21%).
Atmosphere, the gaseous layer that surrounds the Earth, is composed of gases such as oxygen, hydrogen and carbon dioxide. It is divided into layers and ensures survival on the planet.
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The Molar mass of silicon is 28.09 grams/mole
Calculate the number of atoms in a 92.8 mg sample of silicon
Write your answer in scientific notation using three significant figures
what is this difference between a Mm and a mm? which is larger one Mm or one mm
Any seabin limitations
Answer:
The device can collect up to 1.5 kg (3.3 lbs) of waste per day and holds a total of 20 kg (44 lbs) of waste. To illustrate this more vividly: A Seabin can collect up to 90’000 plastic bags, 37’500 coffee cups or 16’500 PET bottles per year.
Explanation:
Not sure what you mean??
If the length of a string increases 2 times but the mass of the string remains constant, the new density of the string will equal the original density multiplied by what factor?
If the length of a string increases 2 times but the mass of the string remains constant, the original density will be multiplied by a factor mathematically given as
v=1.414 times
Will the new density of the string equal the original density multiplied by what factor?Generally, the equation for the volume is mathematically given as
v = sqt(TL/m)
Where
density = mass/length
Therefore
[tex]v2/v1 = \sqrt{L2/L1}[/tex]
[tex]v2/v1 = \sqrt{2}[/tex]
In conclusion,v ratio will give us
v=1.414 times
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1. Which statement is always true when nuclear fusion occurs?
A. The number of protons in the resulting nucleus is less than in each starting nucleus.
B. The number of protons in the resulting nucleus is double that of a starting nucleus.
C. The combined number of portions and neutrons remains constant.
D. The total number of protons and neutrons in each nucleus remains constant.
•
2. Use the equation to answer the question.
2H + 2H—> 4H + energy
1 1 2
Which statement best describes the mass numbers of the atoms in the reaction?
A. There are two atoms with mass numbers of 2.
B. There is one atom with
a mass number of 2.
C. There are two atoms with mass numbers of 1.
D. There is one atom with a mass number of 1.
•
3. How is the mass number calculated for an atom involved in nuclear fusion?
A. It is the number of electrons.
B. It is the number of protons plus electrons.
C. It is the number of neutrons.
D. It is the number of protons plus neutrons.
•
4. Which change will always take place in nuclear fusion?
A. The total charge will be less than before the fusion took place.
B. The nucleus with a smaller mass than any of the reactants will be produced.
C. A nucleus with a greater mass than any of the reactants will be produced.
D. The total charge will be greater than before the fusion took place.
•
5. Which statement best summarizes the way the sun produces energy?
A. Combustion reactions in the sun release large amounts of chemical energy.
B. Fusion reactions in the sun release large amounts of chemical energy.
C. Combustion reactions in the sun convert small amounts of matter into large amounts of energy.
D. Fusion reactions in the sun convert small amounts of matter into large amounts of energy.
Answer:
1. The combined number of protons and neutrons remains constant.
2. There are two atoms with mass numbers of 2.
3. It is the number of protons plus neutrons.
4. A nucleus with a greater mass than any of the reactants will be produced.
5. Fusion reactions in the sun convert small amounts of matter into large amounts of energy.
Balance the following equation. Fill in the blanks
( ? )NaCl + ( ? ) AgNO3 → ( ? )AgCl + ( ? ) NaNO3
NaCl+AgNO_3-->AgCl+NaNO_3
on both sides
Na=1Ag=1Cl=1NO_3=1Hence it's balanced already
Which equation shows how frequency is related to velocity and wavelength?
The equation that shows how frequency is related to velocity and wavelength is f = v / λ (Option A)
What is frequency?This is defined as the number of oscillations made in one second. It is expressed as
Frequency (f) = 1 / period (T)
f = 1 / T
Relationships between frequency, wavelength and velocityThe velocity, frequency and wavelength of a wave are related according to the following equation
v = λf
Making f the subject, we have
f = v / λ
Thus, we can conclude that the correct answer to the question is:
f = v / λ (Option A)
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A student with a cold experiences a fever. The fever results directly from the activity of which body system?
A: Respiratory
B: Immune
C: Circulatory
D: Skeletal
Answer:
its prob B since thats the system that protects the body from harmful substances
Explanation:
Answer:
B since that's the system that protects the body from harmful substances.
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Quantity of atoms in .3521 mol in ZrSiO4
Answer:
look the image
Explanation:
If I add 30mL of water to 125mL of a 0.15M of NaOH solution, what will the molarity of the dilated solution be?
Answer:
.12 M
Explanation:
.15 M / L * .125 L = .01875 Moles
now add 30 ml for total 155 ml = .155 L
.01875 M / .155 L = .12 M
How much energy (in J) is required to raise the temperature of 19.2 g of water by 5.00 oC? (Specific heat capacity of liquid water: 4.184 J/g⋅°C)
What is the pressure exerted by a force of 14.7 N over an area of 0.00482 m²?
Answer:
[tex]p= \frac{F}{A} = \frac{ 14.7 }{0.00482} = 3050 \: Pa[/tex]
2.1 Interpret the results based on your understanding. Indicate deficiencies and excesses. (20)
2.2 How will you correct the deficiencies and/or excesses found in this soil?
Soil nutrients are minerals which are required for growth either small or relatively large quantities
What are soil minerals?Soil minerals are the metallic and non-metallic nutrients found in the soil which are required by plants for growth.
Based on plants requirements, the major nutrients are nitrogen, phosphorus and potassium.
Plants also require other nutrients like copper, zinc, sulfur, iron, etc., in smaller quantities.
Based on the results of the soil test:
The deficiencies nutrients are copper and potassium The excess nutrients are phosphorus, sulfur, iron and zincThe deficiencies and excesses can be corrected by selectively reducing the application of the excess soil nutrients and addition of the deficient nutrients.
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What is the maximum concentration of Ag⁺ that can be added to a 0.00620 M solution of Na₂CO₃ before a precipitate will form? (Ksp for Ag₂CO₃ is 8.10 × 10⁻¹²)
For the maximum concentration of Ag+ is mathematically given as
x = 3.6×10−5
What is the maximum concentration of Ag⁺ that can be added to a 0.00620 M solution of Na₂CO₃ before a precipitate will form?Generally, the Ksp equation for this reaction is mathematically given as
[tex]K_{sp}=[Ag^+]^2[CO_3^{2-}][/tex]
[CO3^2-]=0.00620M
Ksp =[Ag+}^2 x 0.00620
8.1x10^-12 = x^2 x 0.00620
x = [tex]\sqrt{8.1*10^{-12}/0.00620}[/tex]
x = 3.6×10−5
In conclusion, the maximum concentration of Ag⁺ is
x = 3.6×10−5
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12. A voltaic cell consists of a chromium electrode dipped in a 1.20 M chromium (III) nitrate
solution and a tin electrode dipped in a 0.400 M tin (II) nitrate solution. What is the cell
potential at 298 K?
For a voltaic cell consisting of chromium, an electrode dipped in a 1.20 M chromium (III) nitrate solution and a tin electrode dipped in a 0.400 M tin (II) nitrate solution, the cell potential at 298 K is mathematically given as
Ecell = 0.577 V
What is the cell potential at 298 K?Generally, the equation for the Oxidation and Reduction is mathematically given as
Cr(s) ------------------ Cr+3(aq) + 3e- ] x 2 ...O
Sn+2(aq) + 2e- ------------ Sn(s) ] x 3 ...R
Reaction
2 Cr(s) + 3 Sn+2(aq) --------------- 2 Cr+3(aq) + 3 Sn(s)
Therefore
Eicell = - 0.14 - ( - 0.74)
Eicell = 0.60
In conclusion
[tex]Ecell= E0cell - \frac{0.0591}{n} * \frac{log[Cr+3]^2}{ [ Sn+2]^3}[/tex]
[tex]Ecell = 0.60 - \frac{0.0591 }{6} \frac{log( 1.20)^2}{ ( 0.200)^3}[/tex]
Ecell = 0.577 V
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given scientific reason for Nacl dissolves in water
Answer:
Matter is made-up of minute particles. Minute particles of matter have space between them.
So, when common salt is added to water, the particles of salt get into the space between particles of water.
Hence, common salt (Table salt) dissolves in water.
PROBLEM SETS: %BY MASS, % BY VOLUME, MOLARITY, MOLALITY (show your solution)
1. What is the molarity of a solution in which 0.850 grams of ammonium nitrate are dissolved in 345 mL of solution?
2. Calculate the molality of a solution of 13.5g of KF dissolved in 250. g of water.
3. Calculate the molality of a solution containing 16.5 g of dissolved naphthalene (C10H8) in 54.3 g benzene (C6H6).
4. What is the mass percent of each component in the mixture formed by adding 12 g of calcium sulfate, 18 g of sodium nitrate, and 25 g of potassium chloride to 500 g of water?
5. A solution is made by dissolving 125 g of sodium chloride in 1.5 kg of water. What is the percent by mass?
6. What is the percent by volume of a solution formed by added 15 L of acetone to 28 L of water?
The concentration of a substance can be expressed using molarity, molality or percent.
What is concentration?The term concentration has to do with the amount of substance present in solution. Now let us solve the problems individually;
a) Number of moles = 0.850 grams/80 g/mol = 0.011 moles
molarity = 0.011 moles/345 * 10^-3 L = 0.032 M
b) Number of moles = 13.5g /58 g/mol = 0.23 moles
molality = 0.23 moles/250 * 10^-3 Kg = 0.92 m
c) Number of moles = 16.5 g/128 g/mol = 0.13 moles
molality = 0.13 moles/54.3 * 10^-3 Kg =2.39 m
d) Total mass present = 12 g + 18 g + 25 g + 500 g = 555 g
mass percent of calcium sulfate = 12 g/555 g * 100/1 = 2.2 %
mass percent of sodium nitrate = 18 g/ 555 g * 100/1 = 3.2 %
mass percent of potassium chloride = 25 g / 555 g * 100/1 = 4.5%
mass percent of water = 500 g / 555 g * 100/1 =90.1%
e) Total mass present = 125 g + 1500g = 1625 g
Mass percent of NaCl = 125 g/1625 g * 100/1 = 7.7%
f) Total volume of solution = 15 L + 28 L = 43 L
percent by volume of acetone = 15 L/43 L * 100/1 = 34.9%
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Its chemical formula is C17H19NO3. What percent, by mass, is carbon in this compound?
What is the electro negativity difference for CO ?
The electronegativity of carbon is about 2.5 , and that of oxygen is about 3.5 , and naturally, (3.5−2.5=1.0)>0 . So, the electronegativity difference is greater for a C−O single bond than a F−F single bond.
Answer:
1.0
I hope my answer helps you.
6. How many moles of water would require 92.048 kJ of heat to raise its temperature from 34.0 °C to 100.0 °C? (3 marks)
Taking into account the definition of calorimetry, 0.0185 moles of water are required.
CalorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
Mass of water requiredIn this case, you know:
Heat= 92.048 kJMass of water = ?Initial temperature of water= 34 ºCFinal temperature of water= 100 ºCSpecific heat of water = 4.186 [tex]\frac{J}{gC}[/tex]Replacing in the expression to calculate heat exchanges:
92.048 kJ = 4.186 [tex]\frac{J}{gC}[/tex]× m× (100 °C -34 °C)
92.048 kJ = 4.186 [tex]\frac{J}{gC}[/tex]× m× 66 °C
m= 92.048 kJ ÷ (4.186 [tex]\frac{J}{gC}[/tex]× 66 °C)
m= 0.333 grams
Moles of water requiredBeing the molar mass of water 18 [tex]\frac{g}{mole}[/tex], that is, the amount of mass that a substance contains in one mole, the moles of water required can be calculated as:
[tex]amount of moles=0.333 gramsx\frac{1 mole}{18 grams}[/tex]
amount of moles= 0.0185 moles
Finally, 0.0185 moles of water are required.
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Which action would shift this reaction away from solid silver chloride and toward the dissolved ions
A 25.0 g sample of N2 gas, has a volume of 50.0 L and a pressure of 630. mm of Hg. What is the temperature of the gas? Universal Gas Constant, R = 62.4 L.mm Hg/mole.K
Answer:
565.4 K
Explanation:
Remember PV = nRT
630 * 50 = 25/28 * 62.4 T
T = 565.4 kelvin
Calculate the volume of 2.30 moles of gas exerting a pressure of 2.80 atm at 155°C.
Answer:
28.83dm³
Explanation:
Using ideal gas equation
PV=nRT
P=2.80atm
n=2.30
R=0.082
T=155°C (155+273=428Kelvin)
V=nRT/P
V=2.30×0.082×428/2.80
V=28.83dm³
What is the theoretical yield of sodium chloride for the reaction of 55.0 g of Na
D
with 67.2 g Cl2?
g
a. 1.40 x 102 g NaCl
b. 111 g NaCl
c. 55.4 g NaCl
222 g NaCl
[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the concept of Physical chemistry, and Stochiometry.
So we balance the equation as,
2Na + Cl2 ===> 2NaCl
The required reaction is as:
2Na+ Cl2 = 2NaCl
2 moles Na = 2×23 g = 46g,1 mole Cl2 = 2×35.5g=71g
Now,71g Cl2 reacts with 46g Na,
Therefore, 67.2g Cl2 reacts with 46×67.2/71= 43.54g Name
The rest Na = (55–43.54)g=11.46g
That means Cl2 is a limiting reactant.
Again,2 moles NaCl=2(23+35.5)g=117g
Then,71g Cl2 produce 117g NaCl
Therefore,67.2g Cl2 produce 117×67.2/71 = 110.74g NaCl
hence the correct option is, b.) 111 g NaCl
What are renewable resources?
Answer:
Renewable sources are something that can be renewed like
Plants
Trees
etc
uh
Explanation:
Non-renewable for example is you cant renew them at all
there built by the earth themselfs
Like
cole
gemstone
Steel
Metal
etc
How to pay taxes I MEAN
what is galvanization
What is the correct way of representing hydrogen gas alone, in a reaction??
A rubber ball is held 4.0 m above a concave spherical mirror with a radius of curvature of 1.5 m. At time equals zero, the ball is dropped from rest and falls along the principal axis of the mirror. How much time elapses before the ball and its image are at the same location?
The time elapsed when the ball placed above the concave mirror and the image formed would be at the same location is 0.55 s.
Image distanceThe position of the image formed is determined using the followimg mirror formula;
[tex]\frac{1}{f} = \frac{1}{v} + \frac{1}{u}[/tex]
where;
f is the focal length of the mirrorv is the image distanceu is the object distancef = R/2
f = 1.5/2
f = 0.75 m
When the ball and its image is in the same position, u = v
The position of the ball is calculated as;
[tex]\frac{1}{f} = \frac{1}{u} + \frac{1}{u} \\\\\frac{1}{f} = \frac{2}{u} \\\\u = 2f\\\\u = 2(0.75)\\\\u = 1.5 \ m[/tex]
Time of motion of the ballThe time taken for the ball to travel the caluclated distance is determined as;
h = ut + ¹/₂gt²
1.5 = 0 + ¹/₂(9.8)t²
1.5 = 4.9t²
t² = 1.5/4.9
t² = 0.306
t = 0.55 s
Thus, the time elapsed when the ball and its image are at the same location is 0.55 s.
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