12. Suppose the polar bears were running on land instead of swimming. if the polar bear runs
at a speed of about 5.5m/s how far will it travel in 55 seconds?

Answers

Answer 1

the polar bear will travel 302.5m


Related Questions

Two spherically symmetric planets with no atmosphere have the same average density, but planet B has twice the radius of planet A. A small satellite of mass mA has period TA when it orbits planet A in a circular orbit that is just above the surface of the planet. A small satellite of mass mB has period TB when it orbits planet B in a circular orbit that is just above the surface of the planet.

Answers

A period of a satellite is the time taken by the satellite to travel round a

body.

The comparison between the periods  [tex]T_B[/tex], and [tex]T_A[/tex] is [tex]\underline {T_B = \dfrac{\sqrt{2} }{4 } \cdot T_A}[/tex]

Reason:

The period, T, of a satellite is given as follows;

[tex]T = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \cdot M} }[/tex]

Volume of the planet A = [tex]\dfrac{4}{3} \cdot \pi \cdot r^3[/tex]

Mass of planet A, [tex]m_A[/tex] = [tex]\dfrac{4}{3} \cdot \pi \cdot r^3 \times \rho[/tex]

Volume of the planet B = [tex]\dfrac{4}{3} \cdot \pi \cdot (2 \cdot r)^3 = \dfrac{32}{3} \cdot \pi \cdot r^3[/tex]

Mass of planet B, [tex]m_B[/tex] = [tex]\dfrac{32}{3} \cdot \pi \cdot r^3 \times \rho[/tex]

Period of the satellite on planet A, [tex]T_A[/tex], is given as follows;

[tex]T_A = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \times \dfrac{4}{3} \cdot \pi \cdot r^3 \times \rho} } = 2 \cdot \pi \cdot \sqrt{\dfrac{1}{G \times \dfrac{4}{3} \cdot \pi \times \rho} }[/tex]

Period of the satellite on planet B, [tex]T_B[/tex], is given as follows;

[tex]T_B = 2 \cdot \pi \cdot \sqrt{\dfrac{r^3}{G \times \dfrac{32}{3} \cdot \pi \cdot r^3 \times \rho} } = 2 \cdot \pi \cdot \sqrt{\dfrac{1}{G \times \dfrac{32}{3} \cdot \pi \times \rho} }[/tex]

Therefore, get;

[tex]\dfrac{T_A}{T_B} = \dfrac{ 2 \cdot \pi \cdot \sqrt{\dfrac{3}{G \times 4 \cdot \pi \times \rho} }}{ 2 \cdot \pi \cdot \sqrt{\dfrac{3}{G \times 32 \cdot \pi \times \rho} }} = \sqrt{\dfrac{32}{4} } = \sqrt{8} = 2 \cdot \sqrt{2}[/tex]

Therefore, [tex]T_A[/tex] = (2·√2)·[tex]T_B[/tex]

[tex]T_B = \dfrac{T_A}{2 \cdot \sqrt{2} } = \dfrac{\sqrt{2} \cdot T_A}{4 }[/tex]

The comparison between [tex]T_A[/tex] and  [tex]T_B[/tex] is therefore;

[tex]\underline {T_B = \dfrac{\sqrt{2} }{4 } \cdot T_A}[/tex]

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What is the intensity level for a sound of Intensity 10-⁶w/m²​

Answers

Thus, the intensity of the sound level is 63.01 dB.

You have a new goal of saving at least $4,500 over the course of the next year.

You already have $900 saved.

By how much would you need to increase your monthly net savings in order to meet this goal?

Answers

Answer:

You would need to save $300 every month to meet your savings goal.

Explanation:

4,500-900=3,600

3,600/12=300

Answer:

answer is 200

Explanation:

edge 2021

(c) Changing water into vapour is condensation true or false​

Answers

Answer:

true

Explanation:

part A
Explain how the students can measure the distance the cars travel.

part B
Explain how the students could measure the time it takes the cars to travel the distance you explained in the first part.

Answers

Answer:

Part A: By using the formula, distance = speed x time

Part B: By using the formula, time = distance ( calculated in the first part) ÷ speed

Ex 3) A tennis player lobs the tennis ball up in the air during a serve at a rate 3 m/s.
How long will it take the tennis ball to reach its maximum height?

Answers

Explanation:

s=(v^2-u^2)/2g

=(0-3^2)/2*10

= 0.45m

10. Unless a light ray comes into contact with a surface or enters a different material, it
travels in a

Answers

Answer:

Straight Path

Explain what is meant by the elastic limit of a spring.​

Answers

Answer:

The elastic limit of a material is the furthest

point it can be stretched or deformed while

being able to return to its previous shape.

Explanation:

Once a material has gone past its elastic

limit, its deformation is said to be inelastic.

The higher the spring constant, the stiffer

the spring.

Most gasoline engines in today's automobiles are belt driven. This means that the crankshaft, a rod which rotates and drives the
pistons, is timed to the camshaft, the mechanism which actuates the valves, by means of a belt. Starting from rest, assume it
takes t = 0.0320 s for a crankshaft with a radius of r = 3.75 cm to reach 1250 rpm. If the belt does not stretch or slip, calculate
the angular acceleration ay of the larger camshaft, which has a radius of r2 = 7.50 cm, during this time period.

Answers

The angular acceleration of the larger camshaft is 995.72 rad/s².

The given parameters;

initial angular velocity, [tex]\omega _i[/tex] = 0time of motion, t = 0.032 sradius of the crankshaft, r = 3.75 cm final angular speed, [tex]\omega _f[/tex] = 1250 rpm

The angular acceleration of the 3.75 cm camshaft is calculated as follows;

[tex]\omega _f = \omega _i + \alpha t\\\\\omega _f =0 + \alpha t\\\\\omega _f = \alpha t\\\\(1250 \ \frac{rev}{\min} \times \frac{2 \pi \ rad}{rev} \times \frac{1\min}{60 \ s} ) = 0.032 \alpha \\\\130.92 = 0.032\alpha \\\\\alpha = \frac{130.92}{0.032} = 4091.25 \ rad/s^2[/tex]

The angular momentum of the camshaft is calculated as follows;

[tex]I_1 \alpha _1 = I_2 \alpha_2 \\\\\frac{1}{2} mr_1^2 \alpha _1 = \frac{1}{2}m R^2 \alpha_2\\\\r_1^2 \alpha _1 = R^2 \alpha_2\\\\\alpha_2 = \frac{r_1^2 \alpha _1 }{R^2} \\\\\alpha_2 =\frac{(0.037)^2 \times (4091.25)}{(0.075)^2} \\\\\alpha _2 = 995.72 \ rad/s^2[/tex]

Thus, the angular acceleration of the larger camshaft is 995.72 rad/s².

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8. What is the kinetic Energy of the 75 kg skydiver if she is falling at 52 m/s?
Formula:
Variables with units:
Work with Units:
Final Answer with Units:

Answers

Answer:

101,400 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question

m = 75 kg

v = 52 m/s

We have

[tex]k = \frac{1}{2} \times 75 \times {52}^{2} \\ = \frac{1}{2} \times 75 \times 2704 \\ = 75 \times 1352 \\ = 101400[/tex]

We have the final answer as

101,400 J

Hope this helps you

Please show your workmkmmkekdmnesnndndndndn

Answers

Answer:

Explanation:

Remark

The question really is how long does the projectile stay in the air if it was just dropped from a height of 46 meters.

Givens

vi = 0

a = 9.81 m/s^2

h = 46 m

t = ?

Solution

d = vi*t + 1/2 a t^2

46 = 0 + 1/2 * 9.81 * t^2       multiply both sides by 2

92 = 9.81 * t^2                     divide by 9.81

t^2 = 9.38                            Take the square root of both sides

sqrt(t^2) = sqrt(9.38)

t = 3.06 seconds.

In 3.06 seconds the object will hit the ground, thus stopping it. How far horizontally does it go in that time.

d = r * t

d=?

r = 102 m/s

t = 3.06 seconds

d = 102 * 3.06

d = 312.4  meters.

Am I correct? Plz answer ASAP! I will give brainilest:D (Science)

Answers

Answer:

I would agree with your selection.

Explanation:

*Sorry for the bad quality picture!*

A frictionless pendulum with a mass of 0.4 kg and a length of 2.1 m starts at point A, at an angle 0 of 60°. As it swings downward, it passes through point B, which is 30 degrees from equilibrium. What is the kinetic energy of the pendulum at point B?

A) 3.9 J

B) 3.0 J

C) 1.1 J

D) 4.1 J

Answers

The conservation of mechanical energy allows finding the result for the speed of the pendulum when it is at 30º is:

       

The speed is: 3.88 m / s

The conservation of mechanical energy is a theorem of greater importance in physics and ordinary life, it states that if there is no friction force the total mechanistic energy remains constant at all points.

Mechanical energy is the sum of kinetic energy plus all potential energies. In the attachment we see a diagram of the pendulum's movement at the two points of interest.

They indicate that the pendulum is released from an initial angle of θ₁ = 60º, let's find the mechanical energy at that point.

      Em₀ = U = m g h

Where the height is measured from the lowest point of the movement.

      h = L - L cos tea1 = L (1 cos tea1)

The second point of interest occurs for θ₂ = 30º.

At this point part of the energy is indica and part gravitational potential.  

     [tex]Em_f[/tex]  = K + U₂

      [tex]Em_f[/tex] = ½ m v² + m g h ’

There is no friction in the system, therefore mechanical energy is conserved.

       Em₀ = Em₀_f

       mg L (1 - cos θ₁) = ½ m v² + m g L (1 - cos θ₂)

       v² = 2g L (cos θ₂ - cos θ₁)

Let's calculate.

   

       v² = 2 9.8 2.1 (cos 30 - cos 60)

       v² = 41.16 0.366

       v = 3.88 m / s

In conclusion using the conservation of mechanical energy we can find the result for the speed of the pendulum when it is at 30º is:

       

The speed is: 3.88 m / s

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Answer:

3.0 J

Explanation:

Just took the test

Which can occur during a physical change? (SELECT ALL THAT APPLY!.)
The amount of energy within a substance can change.
The shape of a piece of matter can change.
The chemical reaction produces a new substance.
The atoms of the substance can permanently change.

Answers

Answer:

C, B, and D are ones i think i know that can occur during a physical change

Explanation:

Explain why two acetate rods, both charged with silk repel

Answers

Two acetate rods, both charged with silk would repel because they are both have positively charged electrons.

Explanation: Opposite charges attract. Like charges repel.

somebody please help me with this

Answers

Answer:

C.

Explanation:

That is the main part of a cell, apart of the nervous system and controls all the other functions of the cell.

I hope this helped

Brainliest if it did? No pressure!

Have a great day! :D

A person on a bike (m = 90 kg) is traveling 4 m/s at the top of a 2 m hill. What is the biker's total energy?

a) 1,944 J

b) 2,484 J

c) 1,764 J

d) 720 J

Answers

Answer:

Explanation:

Total mechanical energy is

E = mgh + ½mv²

E = m(gh + ½v²)

E = 90(9.8(2.0) + ½4²)

E = 2,484 J answer b)

A person on a bike (m = 90 kg) is traveling 4 m/s at the top of a 2 m hill. the total energy of the biker would be 2484 Joules.

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy.

As given in the problem a person on a bike (m = 90 kg) is traveling 4 m/s at the top of a 2 m hill.

The total kinetic energy of the biker

KE = 1/2 × m × v²

    = 0.5 × 90 × 4²

    = 720

Similarly, the total potential energy of the biker

PE = m × g × h

     =90 × 9.8 × 2

      = 1764 Joules

The total energy of the biker = 720 + 1764

                                                 = 2484 Joules

Thus, the total energy of the biker would be 2484 Joules .

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True or False

In newton's 2nd law, f=ma there is a correlation between the force and acceleration. This supports that there is a causal relationship that acceleration has on the net force.

Answers

Answer: See explanation

Explanation:

Please see attached picture. Due to the fact one of the words in the equation F=ma contains a word not allowed.

What is the velocity of an object tht experiences 5.6m/s^2 and a radius of 3 meters?

Answers

The velocity of the object is 4.1 m/s. Recall that the centripetal acceleration is the acceleration of a body moving in a circular path.

Given that the centripetal acceleration is obtained using the formula;

ac = v^2/r

ac= centripetal acceleration

v = velocity

r = radius

v^2 = rac

v= √ rac

ac = 5.6m/s^2

r = 3 meters

Substituting values;

v = √3 × 5.6m/s^2

v = √16.8

v = 4.1 m/s

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Which of the following formulas describes the change in momentum of an
object?
A. change in momentum = force x time over which force is applied
B. change in momentum = acceleration distance over which
acceleration is applied
C. change in momentum = force x distance over which force is
applied
O D. change in momentum = acceleration time over which
acceleration is applied

Answers

D....................

I need HELP! IMMEDIATELY!!!

Answers

Answer:

Option A

Explanation:

N is Chloroplast, P is a large centralized vacuole and R is the cell wall which are found only in plant cells. Hence, the given cell is a plant cell.

S = Rough Endoplasmic Reticulum

P = Vacuole

O = Nucleus

T = Smooth Endoplasmic Reticulum

U = Golgi Apparatus

N = Chloroplast

U = Cell Membrane

M = Mitochondria

R = Cell wall

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

QUESTION 5 When 235U is bombarded with one neutron, fission occurs and the products are three neutrons, 94Kr and?

a. 139Ba
b. 141Ba
c. 139Ce
d. 139Xe​

Answers

The answer is of the question is A

How 2cos theta ×sin theta is =sin2theta

Answers

Answer:

Can you rewrite that sorry

Explanation:

I need help ASAP please.....

Answers

it represents the distance and time, x, Y show that

a matter can be separated into which of the following choices​

Answers

A matter can be separated into three states.

SolidLiquidGasIn solid state the bonding between atoms is maximum.In liquid state the bonding between atoms is less than solid.In gaseous state the bonding between atoms is minimum
1. solid
2. liquid
3. gas

Consider the frame shown in (Figure 1). The suspended cylinder has a mass of 90 kg .
Determine the x and y components of reaction at pin B on BC using scalar notation.
Determine the x and y components of force at pin C using scalar notation.

Answers

A system in equilibrium has a moment sum of zero and the sum of upward

forces equal to the sum of the downward forces.

The correct values are;

The x and y component of the reaction at pin B are;

Bₓ = 1471.5 N

[tex]B_y[/tex] = 1103.625 N

The x and y component of the force at pin C are;

Cₓ = 588.6 N

[tex]C_y[/tex] = 220.725 N

Reasons:

The weight of the cylinder, W = 90 kg × 9.81 m/s² = 882.9 N

Considering member AB, gives;

[tex]\sum M_A[/tex] = [tex]B_y[/tex] × 2 - [tex]B_x[/tex] × 1.5 = 0 ⇒ [tex]B_y[/tex] = 0.75·Bₓ

Considering member CB, gives;

[tex]\mathbf{\sum M_C}[/tex] = -[tex]B_y[/tex] × 2 + 882.9 × 2.5 = 0 ⇒ [tex]B_y = \dfrac{882.9 \times 2.5}{2} = 1103.625[/tex]

[tex]B_y[/tex] = 0.75·Bₓ ⇒  [tex]B_x = \dfrac{B_y}{0.75} = \dfrac{1103.625}{0.75} = 1471.5[/tex]

The x and y component of the reaction at pin B are;

Bₓ  = 1471.5 N, [tex]B_y[/tex] = 1103.625 N

[tex]\mathbf{\sum F_y}[/tex] = 0 ⇒ -[tex]C_y[/tex] + [tex]B_y[/tex] - 882.9 = 0 ⇒ [tex]-C_y[/tex] + 1103.625 - 882.9 = 0

[tex]C_y[/tex] = 1103.625 - 882.9 = 220.725

[tex]\sum F_x[/tex] = 0 ⇒ -Cₓ + Bₓ - 882.9 = 0 ⇒ -Cₓ + 1471.5 - 882.9 = 0

Cₓ = 588.6

The x and y component of the reaction at pin C are;

Cₓ = 588.6 N, and [tex]C_y[/tex] = 220.725 N

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a father pulls his young daughter on a sled (where the combined mass of his daughter and the sled are 40 kg) with a constant velocity up a snowy hill that is inclined at 14 to the horizontal. a) if the coefficient of kinetic friction between the sled's runners and the snow is 0.15, what is the tension force of the rope on which the father pulls

Answers

Answer:

Explanation:

We are not told what angle the pull rope is to any other reference. That could make a huge difference in the result.

If we ASSUME that the rope pulls parallel to the slope

Then , if T is rope tension

                                  F = ma

T - mgsinθ - μmgcosθ = m(0)

                                 T = mg(sinθ + μcosθ)

                                 T = 40(9.8)(sin14 + 0.15cos14)

                                 T = 151.88677... 150 N

If the rope pulls the sled at a positive angle relative to the slope, As one might expect from an adult holding the rope, then the tension will be increased because only the Tension portion parallel to the slope causes motion in that direction, but will be decreased because the Normal force, and therefore the friction force, of the slope on the sled will be decreased.

How do you explain this arrangement of fossils? What might have happened?

Answers

Answer:

The question lacks a photo to fully answer correctly

If the fossil has its neck bent backwards towards its back, that is the common way to which dinosaurs died.

If the fossil is scattered a bit from its other linking fossil pieces, than it is most likely that the dinosaur was a meal to a predator.

Fossils that are in array but are divided clearly at a section suggests that land moved. Possibly earthquake or Pangea took place.

Answer:

Peripatus, which lived around 570 MYA, is in the top layer of rock. The trilobites that lived later, between 498 MYA and 445 MYA, appear in the bottom layer. Based on superposition, younger layers of rock are expected to be on top. The rock layers have been overturned, placing the younger layer on the bottom.

Explanation:

actually answer plauto

What force causes the passengers in a car to move forward when the car comes to a sudden stop?

Answers

Answer:

You and the car have inertia. If the car comes to a sudden stop, your body tends to keep moving forward. When the car starts moving again, your body tends to stay at rest. You move forward because the car seat exerts an unbalanced force on your body.

Explanation:

This is due to inertia. When the speeding bus stops suddenly, lower part of the body comes to rest while the upper part of the body tends to maintain uniform motion. Hence, the passenger's are thrown forward.

3)
Car A, moving in a straight line at a constant speed of 20. meters per second, is initially 200
meters behind car B, moving in the same straight line at a constant speed of 15 meters per
second. How far must car A travel from this initial position before it catches up with car B?
A)
200 m
B)
1000 m
C)
800 m
D)
400 m

Answers

Answer:

C) 800

Explanation:

Other Questions
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