1.2, 5.8, 3.7, 9.7, 5.5, 0.3, 8.1

what is the Median

Answer:

p = 2a-22

a= p-20

these will help you find the actual value

Step-by-step explanation:

this is not for the actual value

pierre = p

alex = a

p = a+20

p-20 = a

p+22 = 2a

p = 2a-22

Answer:

.674  j / (g-C)

Step-by-step explanation:

Spec heat = heat required to raise 1 gram of substance 1 degree celsius

       Spec heat units : j / (gm-C)

soooo     310 j / (20g * (42-19)C  = .674

Answer:

Greater than

Step-by-step explanation:

The quotient of 3 and 1/4 would be 3/(1/4).

You could then multiply by the inverse of 1/4 to simplify the expression. This would give you [tex]3*\frac{4}{1}[/tex] or just 3 times 4. 3 * 4 = 12.

Since 12 is greater than 3, the quotient of 4 and 1/4 is greater than 3.

Answer:

B: 4/5w = 3/5

Step-by-step explanation:

The length of the rectangle is stated as being 4/5 of the w. (4/5 * w)

The length is also stated specifically as being 3/5m so that will equal 4/5w on the other side of the equation.

Bonus:

You could work out the equation as

4/5w = 3/5m

multiply by 5

4w = 3m

divide by 4

w = 0.75m (or 3/4m)

Check the picture below.

[tex]\textit{area of a rectangle}\\\\ A=Lw~~ \begin{cases} L=length\\ w=width\\[-0.5em] \hrulefill\\ w=3L+7\\ A=48 \end{cases}\implies 48=L(3L+7)\implies 48=3L^2+7L \\\\\\ 0=3L^2+7L-48\implies 0=(3L+16)(L-3) \\\\[-0.35em] ~\dotfill\\\\ 0=3L+16\implies -16=3L\implies -\cfrac{16}{3}=L \\\\[-0.35em] ~\dotfill\\\\ 0=L-3\implies 3=L~~\textit{\Large \checkmark} \\\\[-0.35em] ~\dotfill\\\\ w=3L+7\implies w=3(3)+7\implies w=16[/tex]

notice, we didn't use the negative value of "L", because the length can't be negative.

Answer:

  C. One term has degree 3

Step-by-step explanation:

The quadratic formula is used to find the zeros of degree 2 polynomials. The coefficient of the linear term does not matter, and the coefficient of the x² term may be anything except 0.

If the degree of the polynomial is 3, the quadratic formula does not apply.

Answer:

X = 20

Y = 10√3 or 17.32 or 17.3

Steps given below in the image,

I hope my answer helps you.

Answer:

x = 20

y = 17.32

Step-by-step explanation:

[tex]10 = x \cos 60 \degree \\ \\ \implies \: 10 = x \times \frac{1}{2} \\ \\ \implies \: 10 \times 2= x \\ \\ \implies \: \huge{ \boxed{x = 20}} \\ \\ y = 10 \tan \: 60 \degree \\ \\ \implies \: y = 10 \times \sqrt{3} \\ \\\implies \: y = 10 \times 1.732 \\ \\\implies \: \huge{ \boxed{ y = 17.32}}[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let the total money earned be x

since each of them get equal share, therefore :

[tex]\qquad \tt \dashrightarrow \:5 \times 30 = x[/tex]

[tex]\qquad \tt \dashrightarrow \:x = \$150[/tex]

And here, we used Total earning as the variable in the problem ~

So, correct choice is D

Total persons including Mary=4+1=5

Earnings per person =$30

Total earnings

Option D

8 inches

the area

If the diameter is 8 inches, the radius is 4 inches.

a= Pi* r^2

= 16 Pi square inches.

pi= 3.14159 》 16pi

= 15.2655 sq inch

Answer:

3/$5.79 = 13/x

Step-by-step explanation:

Solve the rational equation by combining expressions and isolating the variable x. Divide $5.79 by three to get the cost of one marker, $1.93. Then multiply the cost of one marker by 13 on the left. This will get the total value which is $25.09.

Answer:

35 seconds

Step-by-step explanation:

Subtract 42 from 7

then you'll 35 secs

Answer:

-3

Step-by-step explanation:

since if you multiply by -3 the sum of both equations will not have an x variable.

Answer:

D

Step-by-step explanation:

Answer:

The value of q = 985

Step-by-step explanation:

==> 25(q-954)=775

=> q-954 = 775/25

=> q-954 = 31

=> q = 31+ 954

=> q = 985

Answer:

q = 985

Step-by-step explanation:

25 (q-954) = 775

q-954 = 775/25

q = 31 + 954

q = 985

The perimeter of this following pattern is

30.8496cm

Answer:

0, 1, 2, 3, 4

Step-by-step explanation:

Multiply each x value by 1/3 then add 2. Since the numerator is 1, you would multipy by one and divide by the denominator of 3, so you really need to divide each x value by 3 then add 2.

-6:

-6/3 = -2

-2 + 2 = 0

-3:

-3/3 = -1

-1 + 2 = 1

0:

0/3 = 0

0 + 2 = 2

3:

3/3 = 1

1 +2 = 3

6:

6/3 = 2

2 + 2 =4

Answer:

x = 3 and y = 0

Step-by-step explanation:

To find the solution where you have two equations is called a System of Equations.

What you do is you notice there are two equations and the let both equations equal each other. We can do this because both equations start with a y. These "y" work like puzzles and you can connect the "x+3" and "2x + 6" together. Then solve for it. Here's what i mean,

y = x+3

y = 2x+6

Now connecting them,

x+3 = 2x+6

Subtract x from both sides

3 = x + 6

Subtract 6 from both sides,

x = -3

Now solve for y,

y = -3 + 3 = 0

So our solution is x = 3 and y = 0.

Answer:

  (x, y) = (-3, 0)

Step-by-step explanation:

Substitution or elimination work well for solving this system of equations.

__

Subtract the first equation from the second.

  (y) -(y) = (2x +6) -(x +3)

  0 = x +3

  -3 = x . . . . . . . subtract 3

  y = (-3) +3 = 0 . . . . use the first equation to find y

  (x, y) = (-3, 0)

__

Use the second equation to substitute for y in the first.

  2x +6 = x +3

  x = -3 . . . . . . . . . subtract x+6 from both sides

  y = (-3) +3 = 0 . . . . find y using the first equation

  (x, y) = (-3, 0)

__

A graphing calculator answers these quickly.

Answer:

2(3-√13) is the answer

Step-by-step explanation:

Given that,

x = \frac{3 - \sqrt{13} }{2}

or, \frac{1}{x} = \frac{2}{3 - \sqrt{13} } (Taking reciprocal on both sides)

We know that,

(a + b)² = a² + b² + 2ab

or, (x \ + \frac{1} {x})^{2} = {x}^{2} + \frac{1}{x {}^{2} } + 2

or, {x}^{2} + \frac{1}{x {}^{2} } = (x \ + \frac{1}{x })^{2} - 2

Now,

or, {x}+ \frac{1}{x } = \frac{3 - \sqrt{13} }{2} + \frac{2}{3 - \sqrt{13} }

or, (3 - \sqrt{13 {})^{2} } + 4

2(3-√13) is the answer

If you didn't understand the frac etc... then I'll attach the f ans file.

Answer:

the amount of space a 3-dimensional object takes up

Step-by-step explanation:

Of the four definition options, the first is the only only that incorporates a three dimension explanation.  The others only describe a two dimension object.  Units for the first would be unit^3.  The other three would only be one-dimensional "units."

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