Answer:
M g - T = M a acceleration of hanging block (M = 2)
2 g - T = 2 a where M = 2
T = 2 g - 2 a
T = 8 * a + 12 N acceleration of blocks on table
2 g - 2 a = 8 a + 12
10 a = 2 g - 12
a = .8 m/s^2 (assuming g = 10 m/s^2)
T = 2 g - 2 a = 2 * 10 - 2 * .8 = 20 - 1.6 = 18.4 N
Check: For blocks on table
a = (18.4 - 12) / 8 = 6.4 / 8 = .8 m/s^2
An object moving at 15 m/s slows uniformly at a rate of 2.0 m/s each second for 5.0 s. What is its final speed?
,a circular loop carrying a current of 40A produce a field of 3*10^8 T at the center what should be the current in the straight conductor so that it produce the same field at a distance equal to the radius if the loop ?
Hi there!
We can begin by deriving the magnetic field strength for a circular loop at its center.
Using Biot-Savart's Law:
[tex]dB = \frac{\mu_0}{4\pi }\frac{idl \times \^r}{r^2}[/tex]
μ₀ = Permeability of free space (Tm/A)
dl = Differential length element
r = radius (m)
We can rather use 'ds' to represent a differential arc length since we are finding the magnetic field for a circular loop.
We must begin by dealing with the cross-product. Luckily, this derivation is simple since the radius vector is ALWAYS perpendicular to the path of integration along the loop's circumference. (ONLY if we are finding the field for the direct center.) Thus, since sin(90) = 1, we can get rid of the cross-product.
Therefore:
[tex]dB = \frac{\mu_0}{4\pi }\frac{ids}{r^2}[/tex]
Now, we can integrate with respect to ds.
[tex]= \frac{\mu_0}{4\pi }\int\limits^{2\pi r}_0 {\frac{i}{r^2}} \, ds\\\\ = \frac{\mu_0}{4\pi }{\frac{i * 2\pi r}{r^2}} \, ds[/tex]
Simplify:
[tex]B = \frac{\mu_0 i_{circle}}{2r}\\[/tex]
Now, for a straight conductor (assuming of infinite length), we know the magnetic field strength equation to be:
[tex]B = \frac{\mu_0 i_{rod}}{2\pi r}[/tex]
Set the two equal.
[tex]\frac{\mu_0 i_{circle}}{2r}= \frac{\mu_0 i_{rod}}{2\pi r}[/tex]
Cancel out '2', μ₀, and 'r':
[tex]i_{circle}}= \frac{ i_{rod}}{\pi }[/tex]
Plug in the given values and solve.
[tex]40\pi = i_{rod}\\\\i_{rod} = \boxed{125.663 A}[/tex]
How does the force of gravity relate to size?
Answer:
Gravitational force is an attraction between masses. The greater the size of the masses, the greater the size of the gravitational force (also called the gravity force). The gravitational force weakens rapidly with increasing distance between masses
Two metal conducting spheres are fixed in place and have charges of 0.00025C 0.00015 C.They are separated by a distance of 0.85 meters. What is the electric force between them
An increase in voltage results in
If the current is held constant, an increase in voltage will result in an increase in resistance.
hope it helps...!!!
by observing ___ we can determine what kind of atoms or molecules are present and their relative abundance
The kind of atoms or molecules are present and their relative abundance can be determined by observing wavelengths.
What is wavelength?Wavelength is the distance between adjacent crest or trough of the wave.
The light travels in the form of wave and particle. It behaves like both. Light ray consist energy of the photons. The kind of atoms or molecules present behave like particle and they have particular wavelength.
Thus, by observing wavelength , we can determine the kind of atoms or molecules are present and their relative abundance.
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In the early 1960s , Cuban anti-communist rebels with the assistance of the United States . Sought to regain control on Cuba from Fidel Castro . This failed military action was called what?
I NEED HELP WILL MARK YOU BRAINLIEST
Answer:
Here is the answer
Here is the answerExplanation:
Here is the answerExplanation:Bay of Pigs Invasion is the answer
Do electrons flow easier with
HIGH resistance or LOW
resistance?
A. low
B.high
Answer:
low.
Explanation:
it makes the flow easier if its lower because, the resistance isn’t pushing as hard against the flow which means that the flow is easier.
A simple pendulum has length of 820mm. Calculate the frequency (g = 9.8 ms -2)
Answer:
[tex]\huge\boxed{\sf f=0.55 \ Hz}[/tex]
Explanation:
Given Data:
Length = l = 820 mm = 0.82 m
Acceleration due to gravity = g = 9.8 ms⁻²
Required:
Frequency = f = ?
Formula:
[tex]\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} }[/tex]
Solution:
[tex]\displaystyle f =\frac{1}{2 \pi} \sqrt{\frac{g}{l} } \\\\Put\ the\ givens\\\\f=\frac{1}{2 \pi} \sqrt{\frac{9.8}{0.82} }\\\\ f = 0.159 \times \sqrt{11.95} \\\\f=0.159 \times 3.457\\\\f=0.55 \ Hz\\\\\rule[225]{225}{2}[/tex]
What controls how fast an object falls?
Answer:
gravity
Explanation:
as the earth rotates on an axis, it causes an effect known as centripetal acceleration with is an acceleration that pulls objects towards the center of the object. in planets, we call this Gravity
Answer:
See below
Explanation:
The initial downward velocity, the acceleration of gravity and air friction all play a part
.......................................
.
Explanation:
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3. A female minke whale has a core body temperature of 35°C and a core/blubber interface temperature of 29°C, with an average blubber thickness of 4.0 cm and thermal conductivity of 0.25 W/mK. At what rate is energy lost from the whale's core by conduction from the core/blubber interface through the blubber to the skin? Assume a skin temperature of 12°C and a total body area of 22 m².
The rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.
Rate of conduction of core/blubber interfaceThe rate of conduction of core/blubber interface is calculated as follows;
[tex]\frac{Q}{t} = \frac{kA\Delta T}{d}[/tex]
where;
k is thermal conductivity = 0.25 W/mkA is the total body area = 22 m²d is thickness of blubber = 4 cm = 0.04 mΔT is change in temperature[tex]\frac{Q}{t} = \frac{kA\Delta T}{d} = \frac{kA}{d} (\Delta Ta \ +\Delta Tb)\\\\\frac{Q}{t} = \frac{kA}{d} ((T_1- T_2 \ +\ T_2-T_3)\\\\\frac{Q}{t} = \frac{0.25 \times 22}{0.04} ( 35 - 29 \ + \ 29 - 12)\\\\\frac{Q}{t} = 137.5( 6 + 17)\\\\\frac{Q}{t} = 3,162.5 \ W[/tex]
Thus, the rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.
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If an amount of heat Q is needed to increase the temperature of a solid metal sphere of diameter D from 4°C to 7°C, the amount of heat needed to increase the temperature of a solid sphere of diameter 2D of the same metal from 4°C to 7°C is
Answer:
Q = c M ΔT where c is the heat capacity and M the mass present
Q2 / Q1 = M2 / M1 since the other factors are the same
M = ρ V where ρ is the density
M = ρ Π (d / 2)^2 where d is the diameter of the sphere
M2 / M1 = (2 D/2)^2 / (D/2)^2 = 4
It will take 4Q heat to heat the second sphere
A few friends went skating on the frozen lake in their hometown. At one point you can hear the ice cracking. What advice can you give them so that the ice does not break and the skaters on the lake are not endangered?
Answer: i'll tell them to be careful. However, the most common is using a drill bit. Take a step close to the shore and listen for cracking. If there is cracking, do not risk going out on the ice. If there is no cracking, take a cordless drill and check the thickness using an extended drill bit.
An airplane on a runway accelerates at 4.0 meters/second2 for 28.0 seconds before takeoff. How far does the plane travel on the runway before
takeoff?
A. 1.6 x 103 meters
B. 1.7 x 103 meters
C. 3.1 x 103 meters
D. 3.3 x 103 meters
Answer:
A
Explanation:
d = 1/2 a t^2 = 1/2 (4)(28^2) = 1568 m ~ 1.6 x 10^3
A body with an initial velocity of 4m/s accelerates uniformly at the rate of 1.2 m/s² over a distance of 20 m. Calculate: (i) the final velocity of the body.(ii) the time in which the body covers that distance. (iii) the average velocity of the body during the journey
v² = u² + 2as
v² = 4² + 2 × 1.2 × 20
v² = 16 + 2 × 12/10 × 20
v² = 16 + 48
v² = 64
v = 8 ms - 1
So,the final velocity is 8 m/sii)
V = u + at
8 = 4 + 1.2 × t
8 - 4 = 1.2t
4 = 12/10 t
4 × 10 /12 = t
3.33 = t
So,the time is 3.33 secondsiii)Average velocity = Displacement/Time
20/3.33
6.006 ms - 1
So,the average velocity is 6.006 m/sSome aliens traveling in a group know that their spaceship launchpad is 25 miles from the gas station where they are right now. How many kilometers is that distance?
The distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.
How many kilometers is that distance?Given that data in the question;
Distance d = 25 milesDistance in kilometers = ?Note that;
1 miles = 1.609 kilometers
Now, the distance in kilometers will be;
distance = 25 miles
distance = ( 25 × 1.609 )kilometers
distance = 40.23km
Therefore, the distance between the aliens traveling in group and their launchpad in kilometers is 40.23km.
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Which of the following can refer to the form of exercise that uses free weights, weight machines, resistance bands, or the weight of the body to put stress on the muscles? A. Strength training B. Weight training C. Resistance training D. All of the above
Answer:
option C...
resistance training is the correct answer
Which of the following is a characteristic of a balanced force?
1) equal in size opposite in direction
2) causes a change in the direction of an object
3) causes a change in the motion of an object
Sonar is used to determine the speed of an object. A 40 kHz signal is sent out, and a 42 kHz signal is returned. Assume the speed of sound is 345 m/s. How fast is the object moving?
Sonar is used to determine the speed of an object. The object is moving at 8.4146 m/s.
What is frequency?The frequency of any wave is defined as the number of cycles per second.
The frequency of the sound received is
f' = f x [(V+Vo /V-Vo)]
where f = 40kHz, f' = 42kHz, V =345 m/s, then the velocity of the observer will be
(V+Vo /V-Vo) = 42/40 =1.05
On rearranging the doppler shift formula, we have
Vo = 0.05 x 345 /2.05
Vo = 8.4146 m/s.
Thus, the object is moving at 8.4146 m/s.
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If an object is moving with a constant velocity of 700 cm/s and starts at an initial position of 20 cm at t=0, what will be the position at t= 0.9 s?
A fish pond appears to be 1m deep but when vewed vertically above the refractive Index of the Water on the pond is 1.5. calculate the real depth formed
Answer:
real depth / apparent depth = R.I.
Real depth = 1.5 x 1 = 1.5 m
Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10^-6 C, q2 = +2.50 x 10^-6 C, and q3 = -2.50 x 10^-6 C. Particles q1 and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m. What is the net force on q2
When q₂ is place between q₁ and q₃, the net force on q₂ is 0.486N.
What is the electrostatic force?The electrostatic force of attraction or repulsion is proportional to the product of magnitude of charges and inversely proportional to the square of distance between them.
Force on q₂ due to q₁
F₁₂ = kq₁q₂ / r₁₂²
Substitute the values provided , we get
F₁₂ = 9 x 10⁹ x 5 x 10⁻⁶ x 2.5 x 10⁻⁶ / (0.5)²
F₁₂ = 0.414 N
Force on q₂ due to q₃ placed at distance 0.25m
F₂₃ =kq₂q₃ / r₂₃²
Substitute the values, we get
F₂₃ = 9 x 10⁹ x 2.5 x 10⁻⁶ x 2.5 x 10⁻⁶ / (0.25)²
F₂₃ = 0.9N
The net force F =F₂₃ -F₁₂
F =0.9 - 0.414 = 0.486 N
Thus, the net force of q₂ is 0.486 N.
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Answer:
0.45
Explanation:
trust me
Consider an object of mass 2kg at rest on a ramp with βs=0.5 and βk=0.4.
If the ramp angle is 60 degrees, how far can the object travel in the first 1 seconds?
The distance traveled by the object in the first 1 second is determined as 0.98 m.
Distance traveled by the objectThe distance traveled by the object is calculated as follows;
F - μkmgcosθ = ma
0 - μkmgcosθ = ma
- μkgcosθ = a
-(0.4)(9.8)cos60 = a
- 1.96 m/s² = a
s = ut + ¹/₂at²
s = 0(1) + ¹/₂(-1.96)(1)²
s = -0.98 m
|s| = 0.98 m
Thus, the distance traveled by the object in the first 1 second is determined as 0.98 m.
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A metallic axle with a diameter of 20mm has to be fitted into a wheel which has a circular hole at its center with diameter of 18.5mm
The coefficient of linear expansion of the metal at the given length is determined as 3.75 x 10⁻⁴/⁰C.
Coefficient of linear expansion of the metalThe coeffcient of linear expansion of the metal is calculated as follows;
ΔL = αLΔT
α = ΔL/LΔT
Where;
α is the coefficient of linear expansionΔL is change in length = 20 mm - 18.5 mm = 1.5 mmΔT is change in temperature = 0 - (-200) = 200°CL is the original length = 20 mmα = (1.5)/(20 x 200)
α = 3.75 x 10⁻⁴/⁰C
The complete question is below:
A metallic axle with a diameter of 20mm has to be fitted into a wheel which has a circular hole at its center with diameter of 18.5mm. To fit the axle into the hole, the axle is dipped into liquid nitrogen at a temperature of -200°C. Calculate the coefficient of linear expansion of the metal.
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A helium balloon has a pressure of 40 psi at 20°C. What will the pressure be at 40°C? Assume constant volume and mass.
Answer:
P V = N R T ideal gas equation
P2 / P1 = T2 / T1 where the other variables are constant
P2 = (T2 / T1) * P1 = (313 / 293) * 40 psi = 42.7 psi
Each box contains information from two different ecosystems about a similar pattern of
interaction between two species that live in close association with each other.
Categorize the type of symbiotic relationships described in the boxed information.
Answer:
What is the interaction between two different species in an ecosystem called?
Interactions between different species in a community are called interspecific interactions—inter- means "between." Different types of interspecific interactions have different effects on the two participants, which may be positive (+), negative (-), or neutral (0).
Explanation:
a 90 N force is applied to a 65 kg mass. the mass will accelerate at
F=m.a
a = F/m
a = 90/65
a = 1.385 m/s²
Answer:
solution
here,
Explanation:
weight = 90N
mass=65kg
acceleration due to gravity (g)=??
Now,
w=m×g
90=65×g
90/65=g
:g=1.38m/s^2
What does the term conservation mean?
A. The process of changing used materials into new products
B. The process of removing pollution from a natural resource
C. Consistent overuse of renewable resources
D. The protection and careful use of natural resources
==============================
[tex] \large \sf \underline{Question:}[/tex]
What does the term conservation mean?==============================
[tex] \large \sf \underline{Answer:}[/tex]
[tex] \qquad \qquad \huge \bold{Option \: D}[/tex]
==============================
[tex] \large \sf \underline{Explanation:}[/tex]
From the term or word itself "Conservation" or in other words conserve, it directly means the protection and careful use of natural resources.==============================
How do you think animals are affected by seasonal change?
Answer:
Animals follow the seasons very closely. Changes in the length of the day or temperature affect the animals' hormone production and cause them to behave according to the season. For that reason, animals instinctively know when it's time for them to mate, build a nest, fly south or stock up on food for the winter.
