The temperature at which the diffusion coefficient have a value of 2.1×10-5 m 2 /s is -47078 K.
Using the relation;
logD = logDo - Ea/2.303RT
D = diffusion coefficient
Do = preexponential
Ea = activation energy
R = gas constant
T = temperature
Substituting values;
log(2.1×10-5)= log (1.1×10-5 ) - 253,300/2.303 × 8.314 × T
log(2.1×10-5) - log (1.1×10-5 ) = - 253,300/2.303 × 8.314 × T
log[2.1×10-5/1.1×10-5] = - 253,300/2.303 × 8.314 × T
0.281 × (2.303 × 8.314 × T) = - 253,300
T = - 253,300/2.303 × 0.281 × 8.314
T = -47078 K
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Draw a conceptual sketch of your laptop. Identify the keyboard, screen, power source, and storage device and etc. using arrows and labels.
Answer:
draw a picture of your computer and label it
Answer: You need to make a drawing for this problem
Explanation:
Make a simple sketch of a laptop, then draw an arrow and label the screen, keyboard, mouse pad, charging port, charging cord, and any extra parts you would like to label.
