1. Describe what the following terms mean
Temperature -
Heat -
Exothermic -
Endothermic -

Answers

Answer 1

Answer :


1- Temperature is the measure of hotness or coldness expressed in terms of any of several scales, including Fahrenheit and Celsius.

2- the quality of being hot high temperature.

3-An exothermic process is one that gives off heat. This heat is transferred to the surroundings.

4- An endothermic process is one in which heat has to be supplied to the system from the surroundings

Related Questions

what is the volume of 0.4 mole of gas at stp? 30 points!

Answers

Answer:

89.6 liters

Explanation:

A STP (standard temperature and pressure) ONE mole of any idea gas will occupies 22.4 liters. So,...

4 moles x 22.4 L/mol = 89.6 liters

8.96 L is the answer

Reading Strategy (page 412)
Relating Text and Visuals As you read, look carefully at Pigures 1
and 2 and read their captions. Complete the table by describing the
work ohown in each figure for more information on this Reading
Strategy, see the Reading and Study Skills in the skills and
Reference Handbook at the end of your textbook
Figure
Direction
of Force
Oirection
of Motion
Is Work
Dono?
20
20
20
412 A101

Answers

Work is said to be done when force moves a distance and the direction of motion is in the direction of applied force.

What is work done?

Work done is defined as the product of applied force and the distance which the applied force moves.

According to Newton's second law of motion the acceleration of a body is inversely to its mass ut directly proportional to the force and takes place in the direction of the applied force.

Therefore, work is done when force moves a distance and the direction of motion is in the direction of applied force.

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Which of the following best
explains why matter changes
from one phase to another?
A. Changes in color causes matter to change
phase.
B. Changes in size causes matter to change
phase.
C. Changes in energy causes matter to change
phase.
D. Changes in volume causes matter to change
phase.

Answers

Answer:

c changes in energy causes matter to change

How many moles of potassium sulfate would you need to prepare 1200 grams of 5.0% potassium sulfate (m/m) solution? Select one: a. 0.34 mols b. 60 mols c. 3.4 mols d. 174 mols​

Answers

Answer:

The moles of potassium that you would need to prepare 1200 g of 5% potassium sulfate solution is 1.538 moles

What is the pH of a 4.5 x 10^-3M HI solution?
A) 0.1
B) 4.8
C) 3.2
D) 2.4

Answers

The answer would be D-2.4

The attractions between anions and cations throughout a crystal are known collectively as.

Answers

The attractions between anions and cations throughout a crystal are known collectively as ionic bonds.

What are ionic bonds?

The ionic bonds are a special type of bond where ions (cations and anions) are mutually attracted.

The ionic bonds are fundamental bonds for the development of certain compounds and molecules.

Ionic bonds may be produced between metal compounds that lose electrons (e-) and non-metals that gain e-.

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Which of the following statements accurately describes energy during the phase change of sublimation?

Energy is released.

Energy slows down.

Energy stays the same.

Energy is absorbed.

Answers

Answer: Your answer is D. Energy is absorbed.

Hope this helps!

Answer:

Energy is absorbed

Explanation:

For sublimation ....let's look at ice as an example

 you must add calories (heat ) to melt the ice and then heat to produce water vapor  .... sublimation requires energy input

Which type of carbon fixation stores carbon dioxide in acid form? a. c3 b. c4 c. cam d. all of the above

Answers

The type of carbon fixation stores carbon dioxide in acid form is CAM i.e. crassulacean acid metabolism.

What are CAM?

CAM stands for crassulacean acid metabolism in this process photosynsthesis is occured at day time but the exchange of gases takes place at night itself only.

In this carbon fixation process, carbon dioxide is stored in the form of organic acid malic acid and losses carbon dioxide at the night time and by doing this it helps in the storage of water.

Hence option (C) is correct.

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Answer:

CAM

Explanation:

Yes the correct answer is option C, ( CAM)  I just took the test.

the number of cobalt atoms in 0.00103 mole of cobalt​

Answers

It’s is 2.75 g of cobalt

Suppose that sequence of bases on one segment of DNA is ATCGGA. What is the sequence of the bases on the complementary segment?
is it
A: ATCGGA
B: CGATTC
C: AGGCTA
D: TAGCCT
And why is it one of those that you picked.

Answers

Answer:

A: ATCGGA

Explanation:

First, think about which base pairs arise in complementary strands of DNA..

Many human epithelial cells produce sticky mucus. Which of the following statements best describes how this mucus functions in nonspecific adaptive immunity?

provides an impenetrable outer covering that cannot be penetrated by most pathogens

assists in the physical removal of pathogens from the body

produces antibodies that will cause pathogen lysis

promotes growth of the body's normal microbiota

Answers

Answer:

The answer is provides an impenetrable outer covering that cannot be penetrated by most pathogens :)

Explanation:

The cells line the skin so then it makes it really difficult for germs to get through. :)

Have an amazing day!!

Uranium-235 has a half-life of 713 million years. Would uranium-235 or carbon-14 be more useful for dating a fossil from Precambrian time? please help im lost on this and its due tomorrow!

Answers

Uranium-235 which has a half-life of 713 million years will best suited in dating a fossil from Precambrian time.

What is a Fossil?

Thi8s is defined as a trace of an animal or plant of a past geologic age that has been preserved in Earth's crust.

The Precambrian time occurred around 4.6 billions years ago and Uranium-235 which having a half-life of 713 million years means it's more useful when compared to carbon-14 which has a half life of 5,370 years.

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A Cu/Cu2+ concentration cell has a voltage of 0.21 V at 25 ∘C . The concentration of Cu2+ in the cathode is 1.6×10−3 molL−1 .
What is the concentration of Cu2+ in the anode?

Answers

For a Cu/Cu2+ concentration cell has a voltage of 0.21 V at 25 ∘C, the concentration  is mathematically given as

c1=2.7*10^6.77m

What is the concentration of Cu2+ in the anode?

Generally, the equation for the Chemical reaction  is mathematically given as

Cu---->cu  +2^e    O

2e+Cu+2  ---->Cu    R

Therefore

[tex]Ecell=\frac{0.0591}{n}log(c2/c1)\\\\0.25=\frac{0.0591}{2}log(1.6*10^{-3}/c1)[/tex]

c1=2.7*10^6.77m

In conclusion, the concentration is

c1=2.7*10^6.77m

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12. Which is true of this cell as the redox reaction is
taking place?
1) The mass of Al electrode will increase, and
the mass of Ni electrode will decrease.
2) The mass of Al electrode will decrease, and
the mass of Ni electrode will increase.
3) The mass of Al electrode will increase, and the
mass of Ni electrode will remain the same.
4) The mass of Al electrode will remain the same,
and the mass of Ni electrode will increase.
Conuri

Answers

I think the answer is 4

Adjust the alkalinity from 70 ppm to 100 ppm in a 250. 000 gallon pool using sodium bicarbonate

Answers

For an adjustment of the alkalinity from 70 ppm to 100 ppm in a 250,000 gallon pool using sodium bicarbonate, the amount of added chemical  is mathematically given as

X=105lbs

What is the amount of added chemical?

Generally, the equation for the Chemical added  is mathematically given as

X=requred usage*desired change/10ppm*pool of gallon/10000

Therefore

X=1.4*(100-70/10)*(250000/10000

X=105lbs

In conclusion, the added chemical

X=105lbs

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Working with a strong acid, such as sulfuric or nitric acid, requires special care to strictly avoid contact with the acid. What should you do if do come in contact with the acid despite your best efforts?.

Answers

Answer:

immediately flush the affected area gently with lukewarm water for at least 30 uninterrupted minutes

Explanation:

If strong acid comes into contact with the skin, immediately wash the affected area gently with lukewarm water for at least 30 minutes and get medical attention immediately.

How to care for acid exposure?

Exposure to strong acids such as sulphuric acid can occur as skin contact, ingestion, or inhalation of vapors. Each kind of exposure can create serious hazards to health and should be managed quickly and appropriately by medical professionals to reduce damage and health risks.

If strong acid comes into contact with the skin, quickly flush the affected area gently with cold water for at least 30 minutes and seek medical attention immediately. If strong acid gets into your eyes, then flush the eye(s) with water for 30 minutes.

If accidentally ingest strong acid, rinse your mouth with water immediately. But do not induce vomiting and continually rinse your mouth with water. If you inhale strong acid aerosols, get fresh air, and medical attention immediately.

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Which of the following could be a compound?

A
two atoms of oxygen bonded together


B
individual atoms of argon


C
hydrogen bonded to oxygen


D
a mixture of oxygen and nitrogen gases

Answers

Answer:

b. Individual atoms of argon

Explanation:

Hope this helps!

-Justin

Flammable liquids are those that have a flashpoint of:.

Answers

Answer:

Flammable liquid is any liquid having a flashpoint at or below 199.4 °F (93 °C).

Explanation:

:)

Flashpoints for flammable liquids are at 100°F. Lower flash points allow for easier ignition of liquids. A liquid's flash point is the lowest temperature at which a concentrated enough layer of vapor accumulates on top of its surface to allow for ignition.

A liquid that is flammable has a flash point* below 37.8 ° C (100 ° F). A flammable liquid has a flash point that ranges from 37.8 to 93.3° C (100 to 200° F), which is above the standard working temperature. Flammable liquids emit a vapor that, at standard working temperatures, is easily ignitable.

The substance ignites more readily the lower the flash point. For instance, petrol is more flammable than ethylene glycol and has a flash point of about -40 degrees C (-40 °F).

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Answer the question 100 POINTS!!

Answers

Answer:

12.979 m:L (3 d.p.)

Explanation:

Combined Gas Law

[tex]\sf \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

Temperature must be in kelvins (K).

To convert Celsius to kelvins, add 273.15.

Volume can be in any unit.

Given values:

P₁ = 0.837 atmV₁ = 17.5 mLT₁ = 48°C = 48 + 273.15 = 321.15 KP₂ = 0.995V₂ = T₂ = 10°C = 10 + 273.15 = 283.15 K

Rearrange the equation to isolate V₂:

[tex]\implies \sf V_2=\dfrac{P_1V_1T_2}{P_2T_1}[/tex]

Substitute the given values into the equation:

[tex]\implies \sf V_2=\dfrac{0.837 \cdot 17.5 \cdot 283.15}{0.995 \cdot 321.15}[/tex]

[tex]\implies \sf V_2=12.979\:mL\:(3\:d.p.)[/tex]

Therefore, the volume at 10°C will be 12.979 mL (3 d.p.).

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Temperatures

T1=273.+48=321KT2=273+10=283K

Apply combined gas law

[tex]\\ \rm\dashrightarrow \dfrac{P1V1}{T1}=\dfrac{P2V2}{T2}[/tex]

[tex]\\ \rm\dashrightarrow V2=\dfrac{P1V1T2}{P2T1}[/tex]

[tex]\\ \rm\dashrightarrow V2=\dfrac{0.837(17.5)(283)}{0.995(321)}[/tex]

[tex]\\ \rm\dashrightarrow V2=12.978mL[/tex]

[tex]\\ \rm\dashrightarrow V2=12.98mL[/tex]

A balanced chemical equation for the decomposition of hydrogen peroxide is:
2H2O2 + 2H2O + O2.
True or false

Answers

Answer:

true

Explanation:

A 300 L sample of hydrogen was compressed to a volume of 200 L at STP. If the initial temperature is 35.0 °C,
what was the initial pressure?

* please show equation!!

brainliest!!

Answers

Answer:

76.210kPa

Explanation:

[tex] \frac{p1v1}{t1} = \frac{p2v2}{t2} \\ p1 = \frac{p2v2t1}{v1t1} \\ p1 = \frac{101.325 \times 200 \times 308}{300 \times 273} \\ p1 = 76.210kpa[/tex]

How may PARTICLES of oxygen ore requried to make 6.7 moles of Carbon Dioxide

Answers

Answer:

0.15 moles

Explanation:

6.7moles x 1 mole co2 over 44.01 g = 0.15 moles

Which type of fuel can only be used in certain geographic areas?
O A. Nuclear
O B. Biomass
O C. Coal
O D. Wind

Answers

Answer:

A. Nuclear

Explanation:

This is because it could cause severe environmental damage in areas inhabited by the public

Please mark brainliest

Answer:

A) Nuculear

Explanation:

Nuclear powerplants are danguorous for the ecosystem and incase of an exsplosion nuclear is the hardest to recover from. Especially if you know the story about Chernobyl blow up. many animals began to grow diffrent mutations and evryone had to evacuate from having desieses and mutations.

Hoped this helped...

Which gland of the endocrine system is located near the brain?

Answers

Answer:

The pituitary gland is located below the brain. :)

how wind can affect the cooling of the air parcels

Answers

Answer:

Wind pushes air parcels even higher in the troposphere, where it is colder. The air parcels will then lose more energy and more rain can happen.

Explanation:

Answer:

Wind propels air packages upward into the troposphere, which is cooler. As a result, the air packets will lose more energy and more rain may fall.

Explanation:

Why Don't Birds Get Electrocuted When They Land on Electric Wires?

Answers

Answer: Because most electrical wires have an outer coating so you don't get electrocuted when you touch them. You could ask why don't you get electrocuted when you touch a phone charger, same answer, same outer coating.

Answer:

The copper in electrical wires is a great conductor, and birds are not great conductors. So the energy will just bypass the birds and keeps moving along the wire.

Explanation:

How many moles of KBr will be produced from 7 moles of BaBr2?
BaBr2 + K2SO4 --> 2 KBr + BaSO4
1 mole KBr
7 moles KBr
3.5 moles KBr
14 moles KBr

Answers

1 mol BaBR2 produces 2mol KBr .

7 mol s of BaBr_2 produces:-

7(2)14mol KBr

Option D is correct

If 40mL of 2.50M HCl neutralizes 500ml. of KOH, what is the molarity of the KOH?

Answers

The molarity of the 500 mL KOH solution needed to neutralize the 40 mL of 2.50 M HCl is 0.2 M

Balanced equation

HCl + KOH —> KCl + H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 1

The mole ratio of the base, KOH (nB) = 1

How to determine the molarity of KOH Volume of acid, HCl (Va) = 40 mLMolarity of acid, HCl (Ma) = 2.5 MVolume of base, KOH (Vb) = 500 mL Molarity of base, KOH (Mb) =?

MaVa / MbVb = nA / nB

(2.5 × 40) / (0.15 × Vb) = 1

100 / (Mb × 500) = 1

Cross multiply

Mb × 500 = 100

Divide both side by 500

Mb = 100 / 500

Mb = 0.2 M

Thus, the molarity of the KOH solution needed is 0.2 M

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how many moles of H2 would be required to produce 37.0 moles of water?

Answers

Hii there !

The reaction accompanying production of water in this case would be -

[tex]\green{ \underline { \boxed{ \sf{H_2+ \frac{1}{2}O_2\longrightarrow H_2O}}}}[/tex]

Thus ,by observing the reaction, we can conclude that 1 mole of Hydrogen (H[tex]_2[/tex])react with 1/2 mole of oxygen(O[tex]_2[/tex])to produce 1 mole of water (H[tex]_2[/tex]O)

[tex]\implies[/tex]Therefore, 37.0 moles of hydrogen(H[tex]_2[/tex]) will be required to produce 37.0 moles of water.

Hope it helps.

How many grams of rock salt, Naci, do you need to add to a 3.78 kg of ice, to get the temperature to drop to -190?​

Answers

1129.9 grams of rock salt, NaCl should be added to a 3.78 kg of ice to get the temperature to drop to -19 °C.

What mass of rock salt is required?

The mass of rock salt required to lower the temperature of ice by 19 °C is determined using the Blagden's Law given below:

[tex]ΔT = iK_fm[/tex]

where;

ΔT = Change in temperature in °Ci = van't Hoff factorKf = molal freezing point depression constantm = molality of the solute in mol solute/kg solvent.

The van't hoff factor for NaCl, i = 2

Kf for water/ice = 1.86 °C kg/mol

molalityof NaCl = (mass/molar massl) / kg of ice

The mass of NaCl is derived as follows:

mass of NaCl = molality × mass of ice × molar mass

molar mass of NaCl = 58.5

mass of ice = 3.78 kg

Let molality of NaCl = X

ΔT = 19 °C

Inputting the values above in the equation of Blagden law:

19 = 2 x 1.86 °C kg/mol x X

X = 5.11 mol/kg

Then, the mass of NaCl will be;

mass of NaCl = 5.11 × 3.78 × 58.5

mass of NaCl = 1129.9 g

Therefore, 1129.9 grams of rock salt, NaCl should be added to a 3.78 kg of ice to get the temperature to drop to -19 °C.

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