Explanation:
The tension on an object is equal to the mass of the object x gravitational force plus/minus the mass x acceleration. Tension Formula Questions: 1) There is a 5 kg mass hanging from a rope.
A rubber ball is dropped and bounces back up. What kind of energy does the ball have at points A, B, and C?
Answer: At poitns A, B, and C the energy is potential to kinetic energy.
Explanation:
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All motion will eventually stop due to the "loss" of energy to___.
a) friction and thermal energy
b) gravity
c) kinetic energy
d) potential energy
Two isotopes of carbon, carbon-12 and carbon-13, have masses of 1.993 10^-26 kg and 2.159 10^-26 kg, respectively. These two isotopes are singly ionized ( e) and each is given a speed of 7.50 10^5 m/s. The ions then enter the bending region of a mass spectrometer where the magnetic field is 0.9000 T.
Required:
Determine the spatial separation between the two isotopes after they have traveled through a half-circle.
Answer:
0.0174 m
Explanation:
Given that:
mass of carbon 12 [tex]m_{c \ 12} = 1.993 \times 10^{-26} \ kg[/tex]
mass of carbon 13 [tex]m_{c \ 13} = 2.159 \times 10^{-26} \ kg[/tex]
Speed V = [tex]7.50 \times 10^ 5 \ m/s[/tex]
[tex]q = 1.6 \times 10^{-19 } \ C[/tex]
B = 0.9000 T
[tex]R_1 = \dfrac{ m_{c \ 12} \ v}{ qB}[/tex]
[tex]R_1 = \dfrac{ 1.993 \times 10^{-26} \ 7.50 \times 10^5}{ 1.6 \times 10^{-19} \times 0.90000}[/tex]
[tex]R_1 =0.1038 \ m[/tex]
[tex]R_2 = \dfrac{ m_{c \ 13} \ v}{ qB}[/tex]
[tex]R_2= \dfrac{2.159 \times 10^{-26} \ 7.50 \times 10^5}{ 1.6 \times 10^{-19} \times 0.90000}[/tex]
[tex]R_2 = 0.1125 \ m[/tex]
The spatial separation (D) = [tex]2R_2 - 2R_1[/tex]
[tex]D = 2(0.1125 \ m) - 2(0.1038 \ m)[/tex]
D = 0.0174 m
A 1500-kg elevator moves upward with constant speed through a vertical distance of 25 m. How much work was done by the tension in the elevator cable
Answer:
367500Joules
Explanation:
Work done is expressed as;
Work done = force × distance
Force = mass × acceleration due to gravity
Force = 1500×9.8
Force = 14700N
Given
Distance covered = 25m
Workdone = 14700×25
Work done = 367500Joules
Hence the work done by the tension in the elevator cable is 367500Joules
Two charges q1 and q2 exert a force of 20 N on each other. If the charge of q1 is doubled, what will the new force be? 1) 40N 2) 80N 3) 20 N 4) 10 N
Given :
Two charges q1 and q2 exert a force of 20 N on each other.
To Find :
If the charge of q1 is doubled, what will the new force be?
1) 40 N 2) 80 N 3) 20 N 4) 10 N
Solution :
We know, electrostatic force between two charges is given by :
[tex]F = \dfrac{kq_1q_2}{r^2}[/tex]
Here, F = 20 N.
[tex]20 = \dfrac{kq_1q_2}{r^2}[/tex]
Now, if [tex]q_1[/tex] is doubled :
[tex]F'= \dfrac{k(2q_1)q_2}{r^2}\\\\F'= 2\dfrac{kq_1q_2}{r^2}\\\\F'= 2\times F\\\\ F'= 2\times 20 \ N\\\\F'= 40 \ N[/tex]
Therefore, if the charge of q1 is doubled, new force will be 40 N.
Luyando wants to have a bit of fun with her wagon. She puts her 12 baby sister, Waluse, on the wagon and pulls it across the floor using a rope at an angle of 22° above the floor. Using the spring balance that mum uses to weigh things in the kitchen, Luyando realises that the tension in the rope is constant and has a value of about 40 . Use the work-energy theorem to find Waluse’s speed after being pulled 4.0 across the living room. The coefficient of friction is 0.2 and the weight of the wagon is 3kg
Answer:
work energy equation
[tex]w.d(external)= \delta \: k.e+ \: \: \ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: w.d(ressesive)[/tex]
Explanation:
first of all we have to find reaction force to find fr
[tex]fr = \mu \: mg \\ mg = reaction \: force(r) \\ f = ma \\ r + 40 \sin(22) - 150 = 0 \\ r = 150 - 40 \sin(22) [/tex]
then let's find friction
[tex]fr = \mu \: r \\ 0.2 \times (150 - 40 \sin(22) )[/tex]
then let's apply work energy principle...its on the 2nd picture
v = 2.3ms^-1pls explain why
two cars start a trip of 200 km at the same time. the first car travels at 90 km/h and the second at 110 km/h. how much more time in minutes does it take for the slower car to reach its destination?
Answer:
5
Explanation:
give thanks pls
Ram covers distance of zoom in 50 seconds what is his speed
Answer:
speed = distance/time
this is the equation substitute your values and get the answer....btw check you question again..
A helium-neon laser (λ = 633 nm) illuminates a single slit and is observed on a screen 1.50 m behind the slit. The distance between the first and second minima in the diffraction pattern is 3.75 mm .
Required:
What is the width (in mm) of the slit?
Answer:
d = 0.25 mm
Explanation:
The position that the Minimal fall in single silt diffraction pattern can be written as
y=λmD/d ..........eqn(1)
(y2 - y1 )= difference of y that exist between first and second minima
D= distance of slit from the screen=1.50m
d= width of the slit
λ= 633 nm = 633×10^-9m
y= position of pth minimal
eqn(1) can be written as
(y2 - y1)= λmD/d .........eqn(2)
If we substitute the given values we have
(y2 - y1 )= [ (2×633×10^-9 × 1.50) /d] -[ (1×633×10^-9 × 1.50) /d]
Simplyfying
(y2 - y1)=(9.495×10^-7)/d
But The distance between the first and second minima in the diffraction pattern = 3.75, which implies that (y2 - y1) = 3.75mm=
✓ we can substitute (y2 - y1)= 3.75mm=3.75 ×10^-3 into expression above
3.75 ×10^-3 =(9.495×10^-7)/d
The we can make "d" subject of the formula
d=(9.495×10^-7)/ (3.75 ×10^-3)
d=0.00025m
d=0.25×10^-3 m
d=0.25 mm
Hence, the width (in mm) of the slit is 0.25mm
As a projectile thrown upward moves in its parabolic path, at what point along its path are the velocity and acceleration vectors for the projectile perpendicular to each other
Answer: Maximum height
Explanation:
Suppose a projectile is thrown at an angle of [tex]\theta[/tex] with velocity u
As the projectile moves upward, its vertical component of velocity decreases due to gravity. While the horizontal component remains the same as there is no acceleration in the horizontal direction.
At maximum height vertical component of velocity is zero. At this instant horizontal component of velocity is perpendicular to the acceleration due to gravity. This can be explained with the diagram.
A rocket engine has a chamber pressure 4 MPa and a chamber temperature of 2000 K. Assuming isentropic expansion through the nozzle, and an exit Mach number of 3.2, what are the static pressure and temperature in the exit plane of the nozzle
This question is incomplete, the complete question is;
A rocket engine has a chamber pressure 4 MPa and a chamber temperature of 2000 K. Assuming isentropic expansion through the nozzle, and an exit Mach number of 3.2, what are the stagnation pressure and temperature in the exit plane of the nozzle? Assume the specific heat ratio is 1.2.
Answer:
- stagnation pressure is 274.993 Mpa
- the stagnation temperature Tt is 4048 K
Explanation:
Given the data in the question;
To determine the stagnation pressure and temperature in the exit plane of the nozzle;
we us the expression;
Pt/P = (1 + (γ-1 / 2) M²)^(γ/γ -1) = ( Tt/T )^(γ/γ -1)
where Pt is stagnant pressure = ?
P is static pressure = 4 MPa = 4 × 10⁶ Pa
Tt is stagnation temperature = ?
T is the static temperature = 2000 K
γ is ratio of specific heats = 1.2
M is Mach number M = 3.2
we substitute
Pt/P = (1 + (γ-1 / 2) M²)^(γ/γ -1)
Pt = P(1 + (γ-1 / 2) M²)^(γ/γ -1)
Pt = 4 × 10⁶(1 + (1.2-1 / 2) 3.2²)^(1.2/1.2 -1)
Pt = 4 × 10⁶ × 68.7484
Pt = 274.993 × 10⁶ Pa
Pt = 274.993 Mpa
Therefore stagnation pressure is 274.993 Mpa
Now, to get our stagnation Temperature
Pt/P = ( Tt/T )^(γ/γ -1)
we substitute
274.993 × 10⁶ Pa / 4 × 10⁶ Pa = ( Tt / 2000 )^(1.2/1.2 -1)
68.7484 = Tt⁶ / 6.4 × 10¹⁹
Tt⁶ = 68.7484 × 6.4 × 10¹⁹
Tt⁶ = 4.3998976 × 10²¹
Tt = ⁶√(4.3998976 × 10²¹)
Tt = 4047.999 ≈ 4048 K
Therefore, the stagnation temperature Tt is 4048 K
The properties of elements can be predicted by which of the following?
Answer:
1 Answer. The Periodic Table can predict the properties of new elements, because it organizes the elements according to their atomic numbers. Creating new elements is not a simple process. Scientists use a particle accelerator to smash light atoms into a thin metallic foil that contains heavier atoms.
Explanation:
Which of the following is NOT an argument for showing that the Earth must be round: a. during an eclipse of the Moon, the shadow of the Earth is always seen to be round b. when ships travel a large distance away, we see their hulls disappear first and their masts disappear last c. the height of the North Star changes as we travel to different latitudes d. photographs of the Earth from space always show a round body e. the Sun is seen blocking different constellations in the course of a year Submit Your Answer
Answer: The correct option is option E (the Sun is seen blocking different constellations in the course of a year.
Explanation:
The earth, which is one of the planets of the solar system that supports life, is shperical in shape. The spherical ( round) shape of the earth is marked by the intervening highlands and oceans on its surface.
Evidence to show that the earth is shperical are:
--> The Lunar eclipse: During an eclipse of the Moon, the shadow of the Earth is always seen to be round.
--> Ships Visibility: When ships travel a large distance away, we see their hulls disappear first and their masts disappear last.
-->Altitude of Polaris (North Star): The height of the North Star changes as we travel to different latitudes. That is ,increases as you move toward the North pole, or decreases as you move toward the equator.
--> Aerial photographs: Photographs of the Earth from space always show a round body.
The statement that doesn't prove that the earth is spherical in shape is (the Sun is seen blocking different constellations in the course of a year). The sun is seen in front of stars blocking different constellation in a year because the earth orbits round the sun in a year and not that it is shperical in shape.
The coefficient of friction on a surface is 0.25. A box requires 100N to slide it across the surface. What is the weight of the box?
A car accelerates from rest at 2 m/s2. After 6 seconds, what is the speed of the car?
Answer:
Vf = 12 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}=v_{o}+a*t\\[/tex]
where:
Vf = final velocity [m/s]
Vo = initial velocity = 0 (stars from the rest)
a = acceleration = 2 [m/s²]
t = time = 6 [s]
Now replacing:
[tex]v_{f}=0+2*6\\v_{f}=12[m/s][/tex]
What is an example of a secondary group?
A. the attendees of a video-gaming conference
B. the employees of Coca-Cola Corporation
C. the members of a family
D. the teachers from the science department
Answer:(D)The teachers from the science department
Explanation:I took the quiz
A strength and conditioning coach recommends that an athlete train by pulling a large amount of mass while sprinting. If action-reaction forces are always equal and opposite, which explanation best describes the action reaction pair acting on the runner ?
A) The runner will not move because the applied force exerted by the runner on the mass will create an equal and opposite frictional force, canceling the applied force
B) The runner will accelerate forward because the applied force exerted by the runner creates an equal and opposite frictional force by the ground, but these forces are exerted on different objects.
С) The runner will accelerate forward because the force of friction by the mass on the runner is always less than the applied force by the runner, resulting in a net force forward
D) The runner will remain motionless because the applied force by the runner in the forward direction is less than the frictional force from the ground, acting in the opposite direction.
Answer:
The correct answer is B)
Explanation:
Solution:
The correct answer is B)
Because,
Runner is applying a force and forwarding ahead which creates equal and opposite frictional force by the ground. But key point here is that, the equal and opposite force is acting on different objects not on the runner. As, friction force will be applied to the heavy mass and the runner by the ground. So, Runner will always apply greater and opposite force than the total friction force that he is experiencing because of heavy mass friction and its friction due to ground in order to move ahead.
For example, if you pull a empty cart with equal and opposite force, then the cart will not move, as the net force is zero. So, in order to move the cart. you have to apply greater and opposite force.
Some one plzzz help
Answer:
138 km
Explanation:
The wind exerts a force of 425 N to the north on a sailboat, while the water exerts a drag force of 325N in the opposite direction. What is the acceleration of the sailboat if the mass is 4100 kg?
Answer:
its n vv
Explanation:
For each of the situations described below, the object considered is undergoing some changes. Among the possible changes you should consider are:
(Q) The object is absorbing or giving off heat.
(T) The object's temperature is changing.
(E) The object's thermal energy is changing.
(W) The object is doing mechanical work or having work done on it.
(C) The objects chemical energy is changing.
For each of the two situations, identify which of the five changes is taking place, indicating the applicable letters Q T U W C (or none) as appropriate while providing your reasoning.
a. An ice cube sits in the open air and is melting.
b. A cylinder with a piston on top contains a compressed gas and is sitting on a thermal reservoir (a large iron block that can provide or take thermal energy as the system needs). After everything has come to thermal equilibrium, the piston is moved upward somewhat (very slowly). The object to be considered is the gas in the cylinder.
Answer: a. (Q), (T), (E)
b. (Q), (T), (E), (W)
Explanation: Thermal Energy and Temperature are closely related: when the temperature rises causing atoms or molecules to move, thermal energy is produced. Thermal energy is the energy within the system.
Mechanical Work is the amount of energy transferred due to an applied force.
Chemical Energy is the energy contained in the bonds of chemical structures of the molecules released when a chemical reaction happens.
Given the explanations, let's analyse the situations:
a. For an ice cube to be melting, it has to be absorbing heat, which means its thermal energy is changing and, consequently, so does its temperature;
b. First, the gas inside the cylinder reaches a thermal equilibrium, which means its thermal energy and temperature changed. Since there were exchange of heat to reach the equilibrium, the gas absorbed or gave off heat. After the equilibrium, when the piston starts to be moved, the energy of the pressure is transferred to the gas, so mechanical work had been done.
A meteor which is moving at a speed of 100 m si
towards Mars is deteced at a height of 207.2 m
from its surface. The meteor reaches the surface of
Mars after 2 s.
What is the gravitational acceleration of Mars?
Answer:
Acceleration due to gravity of Mars
Explanation:
A rock sinks through water at a constant speed. What energy conversion is occurring?
Answer:
Kinetic to potential energy.
Explanation:
A rock sinks through water at a constant speed is a type of kinetic to potential energy conversion. The rock movement refers to kinetic energy whereas sinking in the water represents potential energy due to movement from top to bottom in the water. So we can say that the kinetic to potential energy conversion is occurring in this example.
A flower vase is sitting on a shelf when a gust of wind from an open
window blows it down. If the vase has a mass of 0.6 kg and the shelf is 1.5
m off the ground, what is the gravitational potential energy of the vase
before it falls?
Answer:
8.82 J
Explanation:
Recall that gravitational potential energy is defined as:
U = m * g * h
Then in our case, the gravitational potential energy U would be:
U = 0.6 * 9.8 * 1.5 J = 8.82 J
The figure shows a cube resting on top of a table . If the table rotates and moves the cube in a counterclockwise circle at a constant speed , describe the direction of the acceleration experienced by the cube .
Answer:
Forwarded
Explanation:
A 600-MW steam power plant, which is cooled by a nearby river, has a thermal efficiency of 50 percent. Determine the rate of heat transfer to the river water. Will the actual heat transfer rate be higher or lower than this value
Answer: 600MW
Explanation:
First and foremost, we have to calculate the rate of heat that is supposed to the power plant. This will be:
= 600 / 50%
= 600 / 0.5
= 1200 MW
The rate of heat transfer to the river water will then be:
= 1200 - 600
= 600MW
Therefore, the actual heat transfer rate is thesame as this value as we got 600MW.
Tim’s cow is anemic. The cow is lacking which type of nutrient?
Answer:
Iron deficiency
Explanation:
or more scientifically explained as decreased hemoglobin levels in your blood but still caused by lack of iron.
A 1kg sphere rotates in a circular path of radius 0.2m from rest and it reaches an angular speed of 20rad/sec in 10 second calculate the tangential acceleration ?
Answer:
0.4 m/s²
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 1 kg
Radius (r) = 0.2 m
Angular speed (w) = 20 rad/sec
Time (t) = 10 s
Tangential acceleration (aₜ) =?
Next, we shall determine the angular acceleration (a) of the sphere. This can be obtained as follow:
Angular speed (w) = 20 rad/sec
Time (t) = 10 s
Angular acceleration (a) =?
a = w/t
a = 20/10
a = 2 rad/s²
Finally, we shall determine the tangential acceleration (aₜ) of the sphere. This can be obtained as follow:
The tangential acceleration (aₜ) and the angular acceleration (a) are related according to the equation:
Tangential acceleration (aₜ) = Angular acceleration (a) × Radius (r)
aₜ = ar
With the above formula, we can obtain the tangential acceleration (aₜ) as follow:
Radius (r) = 0.2 m
Angular acceleration (a) = 2 rad/s²
Tangential acceleration (aₜ) =?
aₜ = ar
aₜ = 2 × 0.2
aₜ = 0.4 m/s²
Therefore, the tangential acceleration is 0.4 m/s²
what are the properties of heat
which of the following statements best describes the balls motion ?
Answer:
C
Explanation:
What is magnitude of the acceleration of a particle of mass and charge placed between the plates of a parallel plate capacitor of charge density
Answer:
a = Qo / E0m
Explanation:
The acceleration of a particle of mass m and charge q placed between the plates of a parallel plate capacitor is, [tex]a=\frac{q*E}{m}[/tex]
Let us consider that mass and charge of particle is m and q.
and electric filed between plates of a parallel plate capacitor is E.
The force on a particle between plates of capacitor is given as,
[tex]F=q*E[/tex]
And also, [tex]F=m*a[/tex]
Where a is acceleration of particle.
From above equations,
[tex]m*a=q*E\\\\a=\frac{q*E}{m}[/tex]
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